Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 804 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 30200 people. The population grows by 5% every year. What will the population be after 1 year?
2. 2.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
3. 3.A scooter is worth ₹48000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
4. 4.A scooter is worth ₹47200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
6. 6.A town has 35300 people. The population grows by 5% every year. What will the population be after 1 year?
7. 7.A scooter is worth ₹23500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
8. 8.A town has 50700 people. The population grows by 10% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹46000 at 10% per year for 3 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹38000 at 15% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹15200 at 10% per year for 1 year, compounded every year (in ₹).
13. 13.What amount will ₹11500 grow to in 1 year at 25% per year compound interest (in ₹)?
14. 14.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
15. 15.Find the compound interest on ₹21000 at 20% per year for 3 years, compounded every year (in ₹).
16. 16.What amount will ₹17000 grow to in 2 years at 10% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
18. 18.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
19. 19.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
20. 20.What amount will ₹57700 grow to in 1 year at 20% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹44000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
23. 23.A town has 52300 people. The population grows by 20% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹29300 at 25% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹2100 grow to in 2 years at 20% per year compound interest (in ₹)?
26. 26.What amount will ₹16000 grow to in 3 years at 10% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹22000 at 8% per year for 1 year, compounded every year (in ₹).
28. 28.A scooter is worth ₹6400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
29. 29.What amount will ₹9000 grow to in 3 years at 20% per year compound interest (in ₹)?
30. 30.A town has 51500 people. The population grows by 4% every year. What will the population be after 1 year?
31. 31.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
32. 32.Find the compound interest on ₹9900 at 15% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
34. 34.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹43900 at 20% per year for 2 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
37. 37.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
38. 38.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
39. 39.A scooter is worth ₹30000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
40. 40.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?

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