Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 809 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹41600 at 25% per year for 2 years (in ₹)?
2. 2.A town has 27200 people. The population grows by 25% every year. What will the population be after 3 years?
3. 3.A scooter is worth ₹23800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
4. 4.Find the compound interest on ₹7500 at 20% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹54400 at 5% per year for 2 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹13600 at 5% per year for 2 years (in ₹)?
7. 7.What amount will ₹22000 grow to in 3 years at 10% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹52800 at 15% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹59500 at 10% per year for 2 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹5000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹46100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
14. 14.Find the compound interest on ₹9500 at 20% per year for 3 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹18400 at 10% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹45000 grow to in 2 years at 12% per year compound interest (in ₹)?
17. 17.A town has 2500 people. The population grows by 5% every year. What will the population be after 1 year?
18. 18.A town has 51000 people. The population grows by 10% every year. What will the population be after 3 years?
19. 19.A town has 12000 people. The population grows by 5% every year. What will the population be after 2 years?
20. 20.What amount will ₹39900 grow to in 1 year at 10% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?
22. 22.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
23. 23.A town has 44600 people. The population grows by 8% every year. What will the population be after 1 year?
24. 24.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
25. 25.A town has 38600 people. The population grows by 4% every year. What will the population be after 1 year?
26. 26.What amount will ₹7300 grow to in 1 year at 12% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹16800 at 15% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹7100 at 25% per year for 1 year, compounded every year (in ₹).
29. 29.What amount will ₹9700 grow to in 2 years at 10% per year compound interest (in ₹)?
30. 30.What amount will ₹5200 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.What amount will ₹32400 grow to in 2 years at 25% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹49200 at 25% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹50600 grow to in 1 year at 5% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹23300 at 15% per year for 1 year, compounded every year (in ₹).
36. 36.A scooter is worth ₹42800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
37. 37.A town has 14200 people. The population grows by 12% every year. What will the population be after 1 year?
38. 38.What amount will ₹59000 grow to in 3 years at 10% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹54900 at 10% per year for 1 year, compounded every year (in ₹).

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