Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 813 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹10800 at 10% per year for 1 year, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹14800 at 15% per year for 2 years (in ₹)?
4. 4.What amount will ₹24100 grow to in 1 year at 25% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹39000 at 10% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹54800 at 25% per year for 2 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹7000 at 20% per year for 1 year, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹35600 at 5% per year for 2 years (in ₹)?
10. 10.What amount will ₹45900 grow to in 1 year at 25% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹3200 at 10% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹2800 at 15% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹4000 at 5% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹21600 at 25% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹4000 at 25% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹14300 at 15% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹11400 grow to in 1 year at 15% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
19. 19.What amount will ₹47500 grow to in 2 years at 8% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹6900 at 10% per year for 1 year, compounded every year (in ₹).
21. 21.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
22. 22.A town has 19600 people. The population grows by 5% every year. What will the population be after 2 years?
23. 23.What amount will ₹33000 grow to in 1 year at 12% per year compound interest (in ₹)?
24. 24.A town has 5600 people. The population grows by 15% every year. What will the population be after 2 years?
25. 25.A town has 5800 people. The population grows by 5% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹9200 at 15% per year for 2 years (in ₹)?
27. 27.A scooter is worth ₹29600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
28. 28.Find the compound interest on ₹50000 at 15% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹59200 at 25% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹59300 at 25% per year for 1 year, compounded every year (in ₹).
31. 31.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹54800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹28000 at 10% per year for 1 year, compounded every year (in ₹).
34. 34.A scooter is worth ₹54000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
35. 35.Find the compound interest on ₹50000 at 25% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹34000 at 15% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹28800 at 10% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 35400 people. The population grows by 20% every year. What will the population be after 1 year?
39. 39.What amount will ₹26400 grow to in 2 years at 25% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹12100 at 4% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets