← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 821 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹15200 at 25% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹18800 at 15% per year for 2 years (in ₹)?
  4. 4.A scooter is worth ₹40400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
  6. 6.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
  7. 7.A scooter is worth ₹16200. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  8. 8.A town has 34000 people. The population grows by 5% every year. What will the population be after 2 years?
  9. 9.What amount will ₹35400 grow to in 1 year at 12% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹36000 at 4% per year for 1 year, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹46600 at 20% per year for 2 years, compounded every year (in ₹).
  12. 12.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  13. 13.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹59200 at 15% per year for 2 years (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹41100 at 20% per year for 2 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹50700 at 20% per year for 2 years (in ₹)?
  17. 17.What amount will ₹47000 grow to in 3 years at 10% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
  19. 19.What amount will ₹28100 grow to in 1 year at 20% per year compound interest (in ₹)?
  20. 20.Find the compound interest on ₹16700 at 4% per year for 1 year, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
  22. 22.A scooter is worth ₹42100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  23. 23.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
  24. 24.A town has 22800 people. The population grows by 5% every year. What will the population be after 2 years?
  25. 25.What amount will ₹57300 grow to in 1 year at 15% per year compound interest (in ₹)?
  26. 26.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹26800 at 25% per year for 2 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹20500 at 20% per year for 3 years, compounded every year (in ₹).
  30. 30.A town has 25500 people. The population grows by 20% every year. What will the population be after 1 year?
  31. 31.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  34. 34.A town has 59200 people. The population grows by 5% every year. What will the population be after 1 year?
  35. 35.What amount will ₹22800 grow to in 2 years at 25% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
  37. 37.What amount will ₹20000 grow to in 2 years at 12% per year compound interest (in ₹)?
  38. 38.What amount will ₹32800 grow to in 1 year at 15% per year compound interest (in ₹)?
  39. 39.What amount will ₹45500 grow to in 1 year at 15% per year compound interest (in ₹)?
  40. 40.What amount will ₹34000 grow to in 2 years at 5% per year compound interest (in ₹)?

Answer key

  1. 950
  2. 64
  3. 423
  4. 29189
  5. 1025
  6. 17496
  7. 12960
  8. 37485
  9. 39648
  10. 1440
  11. 20504
  12. 9261
  13. 32448
  14. 1332
  15. 1644
  16. 2028
  17. 62557
  18. 1224
  19. 33720
  20. 668
  21. 408
  22. 40416
  23. 1664
  24. 25137
  25. 65895
  26. 11664
  27. 15075
  28. 16
  29. 14924
  30. 30600
  31. 59488
  32. 3783
  33. 384
  34. 62160
  35. 35625
  36. 25
  37. 25088
  38. 37720
  39. 52325
  40. 37485

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets