Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹40400 at 25% per year for 2 years (in ₹)?
- 2.A town has 42500 people. The population grows by 8% every year. What will the population be after 2 years?
- 3.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹39000 at 15% per year for 1 year, compounded every year (in ₹).
- 5.Find the compound interest on ₹11100 at 15% per year for 1 year, compounded every year (in ₹).
- 6.What amount will ₹30200 grow to in 1 year at 25% per year compound interest (in ₹)?
- 7.What amount will ₹13700 grow to in 1 year at 20% per year compound interest (in ₹)?
- 8.What amount will ₹46800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹57200 at 25% per year for 2 years (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹10000 at 25% per year for 2 years (in ₹)?
- 11.What amount will ₹38500 grow to in 1 year at 5% per year compound interest (in ₹)?
- 12.Find the compound interest on ₹23100 at 4% per year for 1 year, compounded every year (in ₹).
- 13.A scooter is worth ₹30500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 14.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹47500 at 15% per year for 1 year, compounded every year (in ₹).
- 16.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹48400 at 20% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
- 19.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 20.Find the compound interest on ₹11900 at 15% per year for 1 year, compounded every year (in ₹).
- 21.Find the compound interest on ₹11000 at 10% per year for 3 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
- 24.What amount will ₹27000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹6900 at 20% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹13900 at 10% per year for 1 year, compounded every year (in ₹).
- 28.A scooter is worth ₹55500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
- 30.What amount will ₹48800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹53600 at 5% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹57000 at 15% per year for 1 year, compounded every year (in ₹).
- 33.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹29300 at 20% per year for 2 years (in ₹)?
- 35.What amount will ₹40800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 36.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
- 37.Find the compound interest on ₹52300 at 8% per year for 1 year, compounded every year (in ₹).
- 38.A scooter is worth ₹18400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 39.What amount will ₹25700 grow to in 1 year at 8% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
Answer key
- 2525
- 49572
- 80
- 5850
- 1665
- 37750
- 16440
- 73125
- 3575
- 625
- 40425
- 924
- 15616
- 69212
- 7125
- 416
- 1936
- 92
- 85169
- 1785
- 3641
- 828
- 368
- 35937
- 276
- 1986
- 1390
- 53280
- 56
- 76250
- 134
- 8550
- 7566
- 1172
- 44982
- 46305
- 4184
- 17664
- 27756
- 180
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