← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 828 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
  3. 3.A scooter is worth ₹35200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
  6. 6.What amount will ₹32400 grow to in 1 year at 20% per year compound interest (in ₹)?
  7. 7.Find the compound interest on ₹30300 at 8% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹32500 at 4% per year for 1 year, compounded every year (in ₹).
  9. 9.A scooter is worth ₹16000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  10. 10.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹3600 at 15% per year for 2 years (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  13. 13.A town has 20900 people. The population grows by 8% every year. What will the population be after 1 year?
  14. 14.Find the compound interest on ₹58400 at 25% per year for 2 years, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹25600 at 20% per year for 2 years (in ₹)?
  16. 16.What amount will ₹27100 grow to in 1 year at 8% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹16100 at 10% per year for 2 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
  20. 20.What amount will ₹19100 grow to in 1 year at 25% per year compound interest (in ₹)?
  21. 21.Find the compound interest on ₹47800 at 10% per year for 1 year, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹54800 at 12% per year for 1 year, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹28200 at 20% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹28000 at 25% per year for 2 years (in ₹)?
  27. 27.A town has 7600 people. The population grows by 20% every year. What will the population be after 1 year?
  28. 28.Find the compound interest on ₹37800 at 25% per year for 1 year, compounded every year (in ₹).
  29. 29.A scooter is worth ₹20500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  30. 30.A town has 46900 people. The population grows by 10% every year. What will the population be after 1 year?
  31. 31.What is the difference between the compound interest and the simple interest on ₹46000 at 5% per year for 2 years (in ₹)?
  32. 32.What amount will ₹2500 grow to in 1 year at 4% per year compound interest (in ₹)?
  33. 33.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
  34. 34.What amount will ₹26800 grow to in 2 years at 15% per year compound interest (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹20800 at 25% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹2100 at 20% per year for 2 years, compounded every year (in ₹).
  37. 37.A scooter is worth ₹52400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹14200 at 8% per year for 1 year, compounded every year (in ₹).
  40. 40.What amount will ₹40000 grow to in 2 years at 12% per year compound interest (in ₹)?

Answer key

  1. 25168
  2. 360
  3. 31768
  4. 46
  5. 7625
  6. 38880
  7. 2424
  8. 1300
  9. 6750
  10. 1428
  11. 81
  12. 28
  13. 22572
  14. 32850
  15. 1024
  16. 29268
  17. 3381
  18. 36
  19. 60
  20. 23875
  21. 4780
  22. 76
  23. 6576
  24. 1128
  25. 368
  26. 1750
  27. 9120
  28. 9450
  29. 10496
  30. 51590
  31. 115
  32. 2600
  33. 23328
  34. 35443
  35. 1300
  36. 924
  37. 41920
  38. 192
  39. 1136
  40. 50176

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets