Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 2.A town has 48000 people. The population grows by 10% every year. What will the population be after 3 years?
- 3.A scooter is worth ₹25600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹4900 at 10% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹15600 at 10% per year for 1 year, compounded every year (in ₹).
- 6.Find the compound interest on ₹6100 at 20% per year for 2 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹50800 at 15% per year for 2 years (in ₹)?
- 8.What amount will ₹11000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 9.A scooter is worth ₹54100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 10.What amount will ₹41400 grow to in 1 year at 12% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹40800 at 4% per year for 1 year, compounded every year (in ₹).
- 13.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 14.A scooter is worth ₹45000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹20000 at 20% per year for 3 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹3000 at 10% per year for 3 years, compounded every year (in ₹).
- 18.What amount will ₹6400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 19.A scooter is worth ₹13000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 20.A scooter is worth ₹10600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 21.What amount will ₹9200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 22.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
- 23.A town has 46400 people. The population grows by 20% every year. What will the population be after 2 years?
- 24.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹48400 at 25% per year for 2 years, compounded every year (in ₹).
- 26.A town has 22600 people. The population grows by 4% every year. What will the population be after 1 year?
- 27.What amount will ₹8900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 28.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
- 29.A town has 39800 people. The population grows by 20% every year. What will the population be after 2 years?
- 30.Find the compound interest on ₹6000 at 20% per year for 3 years, compounded every year (in ₹).
- 31.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹34000 at 15% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹4000 at 5% per year for 2 years (in ₹)?
- 34.A town has 58000 people. The population grows by 10% every year. What will the population be after 3 years?
- 35.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
- 37.A scooter is worth ₹18400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹17600 at 5% per year for 2 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
Answer key
- 34992
- 63888
- 10800
- 49
- 1560
- 2684
- 1143
- 19008
- 34624
- 46368
- 16668
- 1632
- 24334
- 38088
- 32
- 14560
- 993
- 7056
- 11440
- 9010
- 12167
- 2080
- 66816
- 7625
- 27225
- 23504
- 11125
- 17212
- 57312
- 4368
- 27436
- 765
- 10
- 77198
- 468
- 29169
- 10350
- 648
- 1804
- 35075
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