Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 834 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹52700 at 10% per year for 2 years (in ₹)?
2. 2.A town has 6000 people. The population grows by 25% every year. What will the population be after 1 year?
3. 3.Find the compound interest on ₹24900 at 25% per year for 1 year, compounded every year (in ₹).
4. 4.A scooter is worth ₹22100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
5. 5.What amount will ₹35500 grow to in 3 years at 20% per year compound interest (in ₹)?
6. 6.A town has 22100 people. The population grows by 4% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹53200 at 10% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹48900 at 20% per year for 2 years (in ₹)?
9. 9.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
10. 10.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
11. 11.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹23600 at 15% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹8000 at 25% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹5900 grow to in 2 years at 10% per year compound interest (in ₹)?
16. 16.A town has 28500 people. The population grows by 25% every year. What will the population be after 1 year?
17. 17.What amount will ₹55200 grow to in 2 years at 25% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹11600 at 20% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹16000 at 20% per year for 2 years (in ₹)?
21. 21.What amount will ₹23400 grow to in 1 year at 20% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹55600 at 5% per year for 2 years, compounded every year (in ₹).
23. 23.What amount will ₹58600 grow to in 1 year at 12% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹56000 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹31800 at 10% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹28200 at 12% per year for 1 year, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹8000 at 25% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹4900 at 20% per year for 2 years (in ₹)?
33. 33.A town has 37500 people. The population grows by 12% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹5200 at 20% per year for 2 years (in ₹)?
35. 35.What amount will ₹26300 grow to in 1 year at 15% per year compound interest (in ₹)?
36. 36.A town has 4400 people. The population grows by 10% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹5000 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 12600 people. The population grows by 10% every year. What will the population be after 2 years?
39. 39.What amount will ₹12400 grow to in 2 years at 25% per year compound interest (in ₹)?
40. 40.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?

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