Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 838 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹32000 at 5% per year for 1 year, compounded every year (in ₹).
3. 3.A scooter is worth ₹28900. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
4. 4.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹22700 at 20% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹16000 at 20% per year for 2 years, compounded every year (in ₹).
7. 7.A scooter is worth ₹13600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
8. 8.A town has 14800 people. The population grows by 15% every year. What will the population be after 2 years?
9. 9.A town has 44000 people. The population grows by 15% every year. What will the population be after 2 years?
10. 10.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹38000 at 15% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹6800 at 5% per year for 2 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹15800 at 20% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹18100 at 4% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹35200 at 10% per year for 2 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
18. 18.What amount will ₹55600 grow to in 1 year at 10% per year compound interest (in ₹)?
19. 19.What amount will ₹33000 grow to in 3 years at 20% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹50000 at 15% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
22. 22.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
23. 23.A town has 14500 people. The population grows by 20% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹3600 at 25% per year for 2 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹51600 at 20% per year for 2 years (in ₹)?
26. 26.What amount will ₹9200 grow to in 2 years at 25% per year compound interest (in ₹)?
27. 27.What amount will ₹18300 grow to in 1 year at 20% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹50400 at 15% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹49200 at 5% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹52100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹2700 at 20% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹16000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
34. 34.What amount will ₹6800 grow to in 2 years at 10% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹14000 at 12% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
37. 37.A town has 30800 people. The population grows by 12% every year. What will the population be after 1 year?
38. 38.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
39. 39.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
40. 40.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets