Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 841 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹47500 at 4% per year for 2 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹55200 at 25% per year for 2 years (in ₹)?
3. 3.What amount will ₹35100 grow to in 1 year at 10% per year compound interest (in ₹)?
4. 4.A town has 51600 people. The population grows by 8% every year. What will the population be after 1 year?
5. 5.A scooter is worth ₹11200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
6. 6.Find the compound interest on ₹23600 at 10% per year for 1 year, compounded every year (in ₹).
7. 7.A town has 11600 people. The population grows by 15% every year. What will the population be after 2 years?
8. 8.What amount will ₹49300 grow to in 1 year at 10% per year compound interest (in ₹)?
9. 9.What amount will ₹4800 grow to in 3 years at 25% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
11. 11.What amount will ₹14100 grow to in 1 year at 8% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
13. 13.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹51000 at 4% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹14500 at 4% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹10300 grow to in 2 years at 20% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
19. 19.A town has 7600 people. The population grows by 10% every year. What will the population be after 2 years?
20. 20.What amount will ₹59900 grow to in 1 year at 10% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹13000 at 25% per year for 1 year, compounded every year (in ₹).
22. 22.A scooter is worth ₹39000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
23. 23.Find the compound interest on ₹5500 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹30000 at 15% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹13800 at 20% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
27. 27.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹55000 at 20% per year for 1 year, compounded every year (in ₹).
29. 29.Find the compound interest on ₹7800 at 10% per year for 2 years, compounded every year (in ₹).
30. 30.What amount will ₹19800 grow to in 1 year at 15% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
32. 32.A town has 50000 people. The population grows by 8% every year. What will the population be after 2 years?
33. 33.Find the compound interest on ₹6000 at 5% per year for 2 years, compounded every year (in ₹).
34. 34.A scooter is worth ₹20500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
36. 36.A town has 18200 people. The population grows by 20% every year. What will the population be after 1 year?
37. 37.What amount will ₹26000 grow to in 3 years at 10% per year compound interest (in ₹)?
38. 38.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹22300 at 10% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹10500 at 15% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets