Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 843 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹50000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹30000 at 10% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹22300 at 10% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹2600 at 12% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹24100 at 10% per year for 2 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹51200 at 20% per year for 2 years (in ₹)?
8. 8.A town has 31100 people. The population grows by 10% every year. What will the population be after 1 year?
9. 9.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
10. 10.A scooter is worth ₹13300. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
11. 11.Find the compound interest on ₹20900 at 20% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹19900 at 20% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
15. 15.A town has 10100 people. The population grows by 20% every year. What will the population be after 2 years?
16. 16.Find the compound interest on ₹3600 at 5% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹13800 at 5% per year for 1 year, compounded every year (in ₹).
18. 18.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹6600 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.A town has 13700 people. The population grows by 15% every year. What will the population be after 1 year?
21. 21.Find the compound interest on ₹60000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹45900 at 20% per year for 2 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹9600 at 15% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹9700 at 10% per year for 2 years (in ₹)?
25. 25.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
28. 28.What amount will ₹46400 grow to in 1 year at 12% per year compound interest (in ₹)?
29. 29.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
30. 30.A scooter is worth ₹24600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹57900 at 4% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹45300 grow to in 1 year at 4% per year compound interest (in ₹)?
37. 37.What amount will ₹10600 grow to in 1 year at 10% per year compound interest (in ₹)?
38. 38.What amount will ₹48200 grow to in 1 year at 15% per year compound interest (in ₹)?
39. 39.A town has 17800 people. The population grows by 10% every year. What will the population be after 2 years?
40. 40.What amount will ₹36300 grow to in 2 years at 20% per year compound interest (in ₹)?

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