Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 848 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹3100 at 10% per year for 1 year, compounded every year (in ₹).
2. 2.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
3. 3.What amount will ₹47500 grow to in 3 years at 20% per year compound interest (in ₹)?
4. 4.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
5. 5.What amount will ₹5400 grow to in 1 year at 10% per year compound interest (in ₹)?
6. 6.A scooter is worth ₹14400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
7. 7.What amount will ₹38800 grow to in 1 year at 15% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹49200 at 15% per year for 2 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹23700 at 8% per year for 1 year, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹18800 at 25% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹11400 at 10% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹51100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹38100 at 20% per year for 2 years (in ₹)?
14. 14.A town has 51000 people. The population grows by 10% every year. What will the population be after 3 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹51400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
17. 17.What amount will ₹14800 grow to in 2 years at 15% per year compound interest (in ₹)?
18. 18.A town has 24800 people. The population grows by 5% every year. What will the population be after 1 year?
19. 19.What is the difference between the compound interest and the simple interest on ₹48800 at 10% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹36300 at 5% per year for 1 year, compounded every year (in ₹).
21. 21.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹25500 at 10% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹6400 at 12% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
26. 26.A scooter is worth ₹40400. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
27. 27.What amount will ₹43400 grow to in 1 year at 15% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹2400 at 25% per year for 2 years (in ₹)?
29. 29.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
30. 30.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
31. 31.What amount will ₹24600 grow to in 1 year at 20% per year compound interest (in ₹)?
32. 32.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
33. 33.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹23900 at 20% per year for 2 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
36. 36.A town has 7500 people. The population grows by 8% every year. What will the population be after 2 years?
37. 37.A scooter is worth ₹58400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
38. 38.Find the compound interest on ₹36600 at 10% per year for 2 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹6400 at 5% per year for 2 years (in ₹)?
40. 40.A scooter is worth ₹2800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?

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