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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 85 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹11000 at 12% per year for 1 year, compounded every year (in ₹).
  2. 2.What amount will ₹36000 grow to in 1 year at 10% per year compound interest (in ₹)?
  3. 3.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
  4. 4.A town has 51000 people. The population grows by 10% every year. What will the population be after 3 years?
  5. 5.What is the difference between the compound interest and the simple interest on ₹50200 at 20% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹50400 at 5% per year for 2 years (in ₹)?
  7. 7.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹42800 at 15% per year for 2 years (in ₹)?
  9. 9.What amount will ₹3700 grow to in 1 year at 8% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
  11. 11.A town has 17900 people. The population grows by 10% every year. What will the population be after 1 year?
  12. 12.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
  13. 13.What amount will ₹9200 grow to in 1 year at 10% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹5600 at 10% per year for 2 years (in ₹)?
  15. 15.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  16. 16.What amount will ₹5100 grow to in 1 year at 12% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹10700 at 10% per year for 1 year, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹29200 at 10% per year for 1 year, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹16600 at 10% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
  21. 21.A town has 9600 people. The population grows by 15% every year. What will the population be after 2 years?
  22. 22.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹12400 at 25% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹37200 at 20% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹46400 at 15% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹8800 at 25% per year for 2 years, compounded every year (in ₹).
  29. 29.What is the difference between the compound interest and the simple interest on ₹22000 at 5% per year for 2 years (in ₹)?
  30. 30.What amount will ₹21600 grow to in 2 years at 5% per year compound interest (in ₹)?
  31. 31.Find the compound interest on ₹12500 at 15% per year for 1 year, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹42400 at 4% per year for 1 year, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹26800 at 20% per year for 1 year, compounded every year (in ₹).
  34. 34.What amount will ₹54500 grow to in 1 year at 4% per year compound interest (in ₹)?
  35. 35.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
  37. 37.A town has 45900 people. The population grows by 4% every year. What will the population be after 1 year?
  38. 38.What is the difference between the compound interest and the simple interest on ₹35600 at 5% per year for 2 years (in ₹)?
  39. 39.A scooter is worth ₹23600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  40. 40.Find the compound interest on ₹50400 at 5% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 1320
  2. 39600
  3. 72128
  4. 67881
  5. 2008
  6. 126
  7. 75264
  8. 963
  9. 3996
  10. 63
  11. 19690
  12. 43740
  13. 10120
  14. 56
  15. 13718
  16. 5712
  17. 1070
  18. 2920
  19. 166
  20. 828
  21. 12696
  22. 16
  23. 6975
  24. 20835
  25. 1488
  26. 368
  27. 1044
  28. 4950
  29. 55
  30. 23814
  31. 1875
  32. 1696
  33. 5360
  34. 56680
  35. 18522
  36. 2800
  37. 47736
  38. 89
  39. 13275
  40. 2520

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