Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 853 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹50100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
2. 2.A town has 45000 people. The population grows by 10% every year. What will the population be after 1 year?
3. 3.A scooter is worth ₹58500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
4. 4.What amount will ₹15800 grow to in 1 year at 4% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹12000 at 20% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹47500 at 12% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹44600 grow to in 1 year at 10% per year compound interest (in ₹)?
8. 8.A scooter is worth ₹9200. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
9. 9.Find the compound interest on ₹13400 at 5% per year for 1 year, compounded every year (in ₹).
10. 10.What amount will ₹22800 grow to in 2 years at 10% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
12. 12.A town has 38600 people. The population grows by 10% every year. What will the population be after 2 years?
13. 13.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹32000 at 10% per year for 2 years (in ₹)?
15. 15.What amount will ₹58900 grow to in 1 year at 25% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹7900 at 10% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.What amount will ₹50100 grow to in 1 year at 25% per year compound interest (in ₹)?
19. 19.What amount will ₹40000 grow to in 3 years at 10% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹6800 at 5% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
22. 22.A scooter is worth ₹57200. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
23. 23.Find the compound interest on ₹22500 at 8% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹11400 grow to in 1 year at 15% per year compound interest (in ₹)?
25. 25.What amount will ₹56000 grow to in 1 year at 12% per year compound interest (in ₹)?
26. 26.What amount will ₹41100 grow to in 1 year at 4% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹9000 at 20% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹49800 at 4% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
30. 30.What amount will ₹27500 grow to in 1 year at 4% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹5400 at 10% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹57600 at 8% per year for 1 year, compounded every year (in ₹).
33. 33.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
34. 34.A town has 32800 people. The population grows by 10% every year. What will the population be after 1 year?
35. 35.Find the compound interest on ₹30000 at 25% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹11400 grow to in 1 year at 12% per year compound interest (in ₹)?
37. 37.A town has 2800 people. The population grows by 20% every year. What will the population be after 1 year?
38. 38.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹37200 at 15% per year for 1 year, compounded every year (in ₹).

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