← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 856 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹51200 at 25% per year for 3 years, compounded every year (in ₹).
  2. 2.What amount will ₹43000 grow to in 3 years at 10% per year compound interest (in ₹)?
  3. 3.A town has 6500 people. The population grows by 20% every year. What will the population be after 3 years?
  4. 4.What amount will ₹14300 grow to in 1 year at 4% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹21900 at 10% per year for 1 year, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹39700 at 15% per year for 1 year, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹42100 at 10% per year for 2 years (in ₹)?
  8. 8.What amount will ₹50500 grow to in 1 year at 25% per year compound interest (in ₹)?
  9. 9.A town has 53600 people. The population grows by 5% every year. What will the population be after 1 year?
  10. 10.A town has 59800 people. The population grows by 10% every year. What will the population be after 2 years?
  11. 11.What is the difference between the compound interest and the simple interest on ₹47200 at 25% per year for 2 years (in ₹)?
  12. 12.A town has 50000 people. The population grows by 5% every year. What will the population be after 2 years?
  13. 13.Find the compound interest on ₹55600 at 5% per year for 2 years, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
  15. 15.What amount will ₹59700 grow to in 1 year at 15% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹58400 at 25% per year for 2 years, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹33200 at 25% per year for 2 years (in ₹)?
  18. 18.A town has 9800 people. The population grows by 15% every year. What will the population be after 1 year?
  19. 19.What amount will ₹50700 grow to in 2 years at 10% per year compound interest (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹10000 at 15% per year for 2 years (in ₹)?
  21. 21.What amount will ₹46000 grow to in 2 years at 5% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹18400 at 15% per year for 1 year, compounded every year (in ₹).
  23. 23.A town has 22500 people. The population grows by 12% every year. What will the population be after 2 years?
  24. 24.A town has 9300 people. The population grows by 4% every year. What will the population be after 1 year?
  25. 25.What is the difference between the compound interest and the simple interest on ₹38400 at 5% per year for 2 years (in ₹)?
  26. 26.What amount will ₹18600 grow to in 1 year at 4% per year compound interest (in ₹)?
  27. 27.What amount will ₹28400 grow to in 1 year at 15% per year compound interest (in ₹)?
  28. 28.A town has 50000 people. The population grows by 4% every year. What will the population be after 2 years?
  29. 29.What amount will ₹16200 grow to in 1 year at 5% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹23200 at 15% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹38800 at 12% per year for 1 year, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹11800 at 10% per year for 1 year, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
  37. 37.A town has 11100 people. The population grows by 5% every year. What will the population be after 1 year?
  38. 38.What is the difference between the compound interest and the simple interest on ₹23800 at 10% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹17400 at 20% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹25200 at 15% per year for 2 years (in ₹)?

Answer key

  1. 48800
  2. 57233
  3. 11232
  4. 14872
  5. 2190
  6. 5955
  7. 421
  8. 63125
  9. 56280
  10. 72358
  11. 2950
  12. 55125
  13. 5699
  14. 1908
  15. 68655
  16. 32850
  17. 2075
  18. 11270
  19. 61347
  20. 225
  21. 50715
  22. 2760
  23. 28224
  24. 9672
  25. 96
  26. 19344
  27. 32660
  28. 54080
  29. 17010
  30. 522
  31. 1278
  32. 4656
  33. 432
  34. 1180
  35. 16668
  36. 9568
  37. 11655
  38. 238
  39. 696
  40. 567

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets