Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 859 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹31100 at 10% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹43700 at 25% per year for 1 year, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹9600 at 15% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹47500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
5. 5.Find the compound interest on ₹11200 at 10% per year for 2 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹19200 at 15% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹50000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
9. 9.A town has 12100 people. The population grows by 15% every year. What will the population be after 1 year?
10. 10.A town has 35400 people. The population grows by 10% every year. What will the population be after 1 year?
11. 11.A town has 20700 people. The population grows by 20% every year. What will the population be after 1 year?
12. 12.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
13. 13.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
14. 14.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
15. 15.A town has 37300 people. The population grows by 10% every year. What will the population be after 1 year?
16. 16.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
17. 17.Find the compound interest on ₹2300 at 10% per year for 2 years, compounded every year (in ₹).
18. 18.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
19. 19.Find the compound interest on ₹26900 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹10400 at 5% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹58000 at 20% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹14000 at 5% per year for 2 years (in ₹)?
26. 26.What amount will ₹51300 grow to in 1 year at 8% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹25500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
30. 30.Find the compound interest on ₹53400 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹29000 grow to in 3 years at 10% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
33. 33.What amount will ₹11000 grow to in 3 years at 20% per year compound interest (in ₹)?
34. 34.A scooter is worth ₹54500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
35. 35.A town has 54600 people. The population grows by 10% every year. What will the population be after 1 year?
36. 36.Find the compound interest on ₹26700 at 25% per year for 1 year, compounded every year (in ₹).
37. 37.What amount will ₹56800 grow to in 2 years at 5% per year compound interest (in ₹)?
38. 38.A town has 17500 people. The population grows by 12% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
40. 40.What amount will ₹57000 grow to in 1 year at 12% per year compound interest (in ₹)?

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