← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 863 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹47400 at 12% per year for 1 year, compounded every year (in ₹).
  2. 2.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹55100 at 10% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹42400 at 25% per year for 2 years (in ₹)?
  5. 5.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹8400 at 25% per year for 2 years (in ₹)?
  7. 7.A scooter is worth ₹48000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  8. 8.What amount will ₹57000 grow to in 3 years at 10% per year compound interest (in ₹)?
  9. 9.What amount will ₹17500 grow to in 2 years at 12% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹2300 at 12% per year for 1 year, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹25600 at 25% per year for 3 years, compounded every year (in ₹).
  13. 13.A scooter is worth ₹42800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  14. 14.Find the compound interest on ₹48000 at 5% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹55300 at 15% per year for 1 year, compounded every year (in ₹).
  16. 16.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  17. 17.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  18. 18.A town has 12500 people. The population grows by 12% every year. What will the population be after 2 years?
  19. 19.What amount will ₹12900 grow to in 1 year at 20% per year compound interest (in ₹)?
  20. 20.A town has 26000 people. The population grows by 10% every year. What will the population be after 3 years?
  21. 21.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹42600 at 4% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹36800 grow to in 1 year at 10% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹24000 at 25% per year for 2 years (in ₹)?
  25. 25.What amount will ₹44200 grow to in 1 year at 8% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹14000 at 15% per year for 2 years (in ₹)?
  27. 27.A town has 23300 people. The population grows by 5% every year. What will the population be after 1 year?
  28. 28.A scooter is worth ₹10000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  29. 29.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹4100 at 12% per year for 1 year, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹59100 at 10% per year for 2 years, compounded every year (in ₹).
  32. 32.A scooter is worth ₹28200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  33. 33.Find the compound interest on ₹55600 at 25% per year for 2 years, compounded every year (in ₹).
  34. 34.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  35. 35.What amount will ₹54800 grow to in 1 year at 10% per year compound interest (in ₹)?
  36. 36.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
  37. 37.What amount will ₹14000 grow to in 2 years at 5% per year compound interest (in ₹)?
  38. 38.A town has 43900 people. The population grows by 12% every year. What will the population be after 1 year?
  39. 39.A scooter is worth ₹7500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?

Answer key

  1. 5688
  2. 18522
  3. 11571
  4. 2650
  5. 46305
  6. 525
  7. 20250
  8. 75867
  9. 21952
  10. 4576
  11. 276
  12. 24400
  13. 24075
  14. 2400
  15. 8295
  16. 40204
  17. 1261
  18. 15680
  19. 15480
  20. 34606
  21. 468
  22. 1704
  23. 40480
  24. 1500
  25. 47736
  26. 315
  27. 24465
  28. 7500
  29. 6656
  30. 492
  31. 12411
  32. 26790
  33. 31275
  34. 128
  35. 60280
  36. 29744
  37. 15435
  38. 49168
  39. 6912
  40. 576

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets