Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 865 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹28500 at 12% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹54400 at 15% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹44400 at 25% per year for 2 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹5600 at 15% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹30300 at 15% per year for 1 year, compounded every year (in ₹).
8. 8.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
9. 9.A town has 11200 people. The population grows by 15% every year. What will the population be after 2 years?
10. 10.What amount will ₹20000 grow to in 3 years at 10% per year compound interest (in ₹)?
11. 11.A scooter is worth ₹54500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
13. 13.What amount will ₹13000 grow to in 3 years at 20% per year compound interest (in ₹)?
14. 14.A scooter is worth ₹12000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
15. 15.A scooter is worth ₹35200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
16. 16.Find the compound interest on ₹17400 at 20% per year for 1 year, compounded every year (in ₹).
17. 17.A scooter is worth ₹37200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
18. 18.What amount will ₹47500 grow to in 3 years at 20% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹2800 at 5% per year for 2 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹18800 at 5% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
22. 22.What amount will ₹37000 grow to in 3 years at 20% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
24. 24.What amount will ₹28100 grow to in 2 years at 20% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹6800 at 25% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
27. 27.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
28. 28.What amount will ₹48300 grow to in 1 year at 4% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹10600 at 10% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹4500 at 20% per year for 3 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹52000 at 10% per year for 2 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹14000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
33. 33.A scooter is worth ₹10500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
34. 34.What amount will ₹55500 grow to in 1 year at 5% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹19200 at 25% per year for 3 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹48300 at 15% per year for 1 year, compounded every year (in ₹).
37. 37.Find the compound interest on ₹51300 at 25% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 36000 people. The population grows by 20% every year. What will the population be after 3 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹51000 at 10% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?

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