Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 867 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 34400 people. The population grows by 5% every year. What will the population be after 1 year?
2. 2.What amount will ₹4200 grow to in 1 year at 25% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹58400 at 25% per year for 2 years (in ₹)?
4. 4.What amount will ₹17400 grow to in 2 years at 10% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹15100 at 20% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹39600 at 15% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹7300 at 12% per year for 1 year, compounded every year (in ₹).
9. 9.Find the compound interest on ₹51600 at 4% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
12. 12.What amount will ₹14700 grow to in 1 year at 12% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹28300 at 10% per year for 2 years (in ₹)?
14. 14.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹58000 at 8% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹43700 grow to in 1 year at 12% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹56700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
18. 18.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
19. 19.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
20. 20.A town has 57500 people. The population grows by 4% every year. What will the population be after 2 years?
21. 21.A scooter is worth ₹54200. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
22. 22.A scooter is worth ₹38000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
23. 23.Find the compound interest on ₹49000 at 12% per year for 1 year, compounded every year (in ₹).
24. 24.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
25. 25.Find the compound interest on ₹14200 at 12% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹8900 at 10% per year for 1 year, compounded every year (in ₹).
27. 27.Find the compound interest on ₹36000 at 10% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹32400 at 15% per year for 1 year, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹44400 at 20% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹40000 at 25% per year for 2 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹26200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
33. 33.Find the compound interest on ₹10400 at 10% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
35. 35.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?
36. 36.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹13100 at 10% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
39. 39.What amount will ₹10000 grow to in 3 years at 10% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹30600 at 5% per year for 1 year, compounded every year (in ₹).

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