Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 874 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹41000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
2. 2.A scooter is worth ₹34000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
3. 3.What amount will ₹39200 grow to in 1 year at 8% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹11200 at 25% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹26200 at 10% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹23600 at 15% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹8900 at 10% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹14900 at 4% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹57600 at 25% per year for 2 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
12. 12.A town has 12000 people. The population grows by 10% every year. What will the population be after 3 years?
13. 13.Find the compound interest on ₹9800 at 10% per year for 2 years, compounded every year (in ₹).
14. 14.A town has 56400 people. The population grows by 25% every year. What will the population be after 2 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹9600 at 5% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
17. 17.A scooter is worth ₹25600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹43500 at 20% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹20000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
20. 20.A scooter is worth ₹54500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
22. 22.A town has 2400 people. The population grows by 25% every year. What will the population be after 1 year?
23. 23.What amount will ₹60000 grow to in 3 years at 20% per year compound interest (in ₹)?
24. 24.What amount will ₹28900 grow to in 1 year at 5% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹2200 at 10% per year for 1 year, compounded every year (in ₹).
26. 26.A town has 20000 people. The population grows by 4% every year. What will the population be after 2 years?
27. 27.What is the difference between the compound interest and the simple interest on ₹60000 at 15% per year for 2 years (in ₹)?
28. 28.What amount will ₹59200 grow to in 2 years at 5% per year compound interest (in ₹)?
29. 29.A town has 2300 people. The population grows by 4% every year. What will the population be after 1 year?
30. 30.Find the compound interest on ₹15500 at 20% per year for 3 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹27200 at 5% per year for 1 year, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹32500 at 10% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹17200 at 10% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹4200 at 4% per year for 1 year, compounded every year (in ₹).
35. 35.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
36. 36.A town has 43000 people. The population grows by 20% every year. What will the population be after 3 years?
37. 37.What is the difference between the compound interest and the simple interest on ₹25200 at 15% per year for 2 years (in ₹)?
38. 38.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹17600 at 5% per year for 2 years (in ₹)?
40. 40.A town has 48600 people. The population grows by 8% every year. What will the population be after 1 year?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets