Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 878 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 47900 people. The population grows by 12% every year. What will the population be after 1 year?
2. 2.A scooter is worth ₹49200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹3600 at 8% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹57900 at 10% per year for 2 years (in ₹)?
5. 5.What amount will ₹55000 grow to in 1 year at 15% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹13100 at 15% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
8. 8.A town has 36900 people. The population grows by 10% every year. What will the population be after 1 year?
9. 9.Find the compound interest on ₹25500 at 20% per year for 3 years, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹40100 at 10% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹20400 at 25% per year for 2 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
13. 13.What amount will ₹39000 grow to in 3 years at 10% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹30000 at 5% per year for 2 years (in ₹)?
15. 15.What amount will ₹35600 grow to in 1 year at 8% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹58800 at 20% per year for 1 year, compounded every year (in ₹).
17. 17.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
18. 18.A scooter is worth ₹11200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
19. 19.Find the compound interest on ₹44800 at 5% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹25200 at 25% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹28800 grow to in 3 years at 25% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹24000 at 10% per year for 3 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
24. 24.A town has 18900 people. The population grows by 10% every year. What will the population be after 1 year?
25. 25.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹8400 at 25% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹50000 grow to in 2 years at 15% per year compound interest (in ₹)?
28. 28.A town has 53300 people. The population grows by 15% every year. What will the population be after 1 year?
29. 29.A town has 38000 people. The population grows by 20% every year. What will the population be after 1 year?
30. 30.What amount will ₹43700 grow to in 1 year at 25% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹27600 at 15% per year for 2 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
34. 34.A scooter is worth ₹4300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
35. 35.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹21300 at 20% per year for 1 year, compounded every year (in ₹).
37. 37.A town has 14400 people. The population grows by 25% every year. What will the population be after 3 years?
38. 38.What amount will ₹14200 grow to in 2 years at 20% per year compound interest (in ₹)?
39. 39.A town has 4000 people. The population grows by 20% every year. What will the population be after 3 years?
40. 40.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).

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