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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 88 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹11500 at 20% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
  3. 3.What amount will ₹11200 grow to in 2 years at 5% per year compound interest (in ₹)?
  4. 4.What amount will ₹28400 grow to in 2 years at 10% per year compound interest (in ₹)?
  5. 5.What amount will ₹20500 grow to in 1 year at 8% per year compound interest (in ₹)?
  6. 6.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
  7. 7.What amount will ₹51400 grow to in 1 year at 15% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹21600 at 25% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
  10. 10.A scooter is worth ₹12000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  11. 11.What amount will ₹37600 grow to in 1 year at 10% per year compound interest (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹56400 at 10% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹52700 at 4% per year for 1 year, compounded every year (in ₹).
  14. 14.A town has 50100 people. The population grows by 20% every year. What will the population be after 2 years?
  15. 15.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  16. 16.A scooter is worth ₹27500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  17. 17.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹26300 at 12% per year for 1 year, compounded every year (in ₹).
  21. 21.A scooter is worth ₹13100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  22. 22.What amount will ₹29900 grow to in 1 year at 25% per year compound interest (in ₹)?
  23. 23.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹16800 at 20% per year for 1 year, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹4900 at 20% per year for 2 years, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
  27. 27.A scooter is worth ₹60000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  28. 28.A scooter is worth ₹19000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  29. 29.A town has 11400 people. The population grows by 10% every year. What will the population be after 1 year?
  30. 30.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹32700 at 10% per year for 1 year, compounded every year (in ₹).
  32. 32.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
  33. 33.What amount will ₹56700 grow to in 1 year at 4% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹4100 at 15% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹56800 at 25% per year for 2 years (in ₹)?
  38. 38.A town has 21400 people. The population grows by 12% every year. What will the population be after 1 year?
  39. 39.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
  40. 40.What amount will ₹20400 grow to in 2 years at 5% per year compound interest (in ₹)?

Answer key

  1. 460
  2. 96
  3. 12348
  4. 34364
  5. 22140
  6. 28224
  7. 59110
  8. 5400
  9. 65856
  10. 6750
  11. 41360
  12. 564
  13. 2108
  14. 72144
  15. 24334
  16. 21296
  17. 34496
  18. 612
  19. 324
  20. 3156
  21. 10480
  22. 37375
  23. 12167
  24. 3360
  25. 2156
  26. 7632
  27. 50784
  28. 17480
  29. 12540
  30. 30
  31. 3270
  32. 31250
  33. 58968
  34. 2448
  35. 144
  36. 615
  37. 3550
  38. 23968
  39. 21632
  40. 22491

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