Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹11500 at 20% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
- 3.What amount will ₹11200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 4.What amount will ₹28400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 5.What amount will ₹20500 grow to in 1 year at 8% per year compound interest (in ₹)?
- 6.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 7.What amount will ₹51400 grow to in 1 year at 15% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹21600 at 25% per year for 1 year, compounded every year (in ₹).
- 9.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 10.A scooter is worth ₹12000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 11.What amount will ₹37600 grow to in 1 year at 10% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹56400 at 10% per year for 2 years (in ₹)?
- 13.Find the compound interest on ₹52700 at 4% per year for 1 year, compounded every year (in ₹).
- 14.A town has 50100 people. The population grows by 20% every year. What will the population be after 2 years?
- 15.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 16.A scooter is worth ₹27500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 17.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹26300 at 12% per year for 1 year, compounded every year (in ₹).
- 21.A scooter is worth ₹13100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 22.What amount will ₹29900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 23.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹16800 at 20% per year for 1 year, compounded every year (in ₹).
- 25.Find the compound interest on ₹4900 at 20% per year for 2 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
- 27.A scooter is worth ₹60000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 28.A scooter is worth ₹19000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 29.A town has 11400 people. The population grows by 10% every year. What will the population be after 1 year?
- 30.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹32700 at 10% per year for 1 year, compounded every year (in ₹).
- 32.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 33.What amount will ₹56700 grow to in 1 year at 4% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹4100 at 15% per year for 1 year, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹56800 at 25% per year for 2 years (in ₹)?
- 38.A town has 21400 people. The population grows by 12% every year. What will the population be after 1 year?
- 39.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 40.What amount will ₹20400 grow to in 2 years at 5% per year compound interest (in ₹)?
Answer key
- 460
- 96
- 12348
- 34364
- 22140
- 28224
- 59110
- 5400
- 65856
- 6750
- 41360
- 564
- 2108
- 72144
- 24334
- 21296
- 34496
- 612
- 324
- 3156
- 10480
- 37375
- 12167
- 3360
- 2156
- 7632
- 50784
- 17480
- 12540
- 30
- 3270
- 31250
- 58968
- 2448
- 144
- 615
- 3550
- 23968
- 21632
- 22491
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