Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 883 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹20900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
2. 2.A town has 36800 people. The population grows by 20% every year. What will the population be after 1 year?
3. 3.Find the compound interest on ₹10400 at 8% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹27100 at 12% per year for 1 year, compounded every year (in ₹).
5. 5.A town has 35200 people. The population grows by 25% every year. What will the population be after 2 years?
6. 6.What amount will ₹17400 grow to in 1 year at 4% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹2400 at 25% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹24300 at 10% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹30500 at 20% per year for 3 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
12. 12.What amount will ₹18600 grow to in 1 year at 20% per year compound interest (in ₹)?
13. 13.A town has 34000 people. The population grows by 5% every year. What will the population be after 2 years?
14. 14.Find the compound interest on ₹50000 at 12% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹24100 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹57200 at 10% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹55600 grow to in 2 years at 5% per year compound interest (in ₹)?
18. 18.What amount will ₹19900 grow to in 1 year at 4% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹8600 at 10% per year for 2 years, compounded every year (in ₹).
20. 20.What amount will ₹20000 grow to in 2 years at 25% per year compound interest (in ₹)?
21. 21.A scooter is worth ₹15000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
23. 23.A town has 7100 people. The population grows by 20% every year. What will the population be after 1 year?
24. 24.A scooter is worth ₹22600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹23200 at 25% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹39000 at 10% per year for 3 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹3600 at 25% per year for 2 years (in ₹)?
28. 28.What amount will ₹31700 grow to in 1 year at 12% per year compound interest (in ₹)?
29. 29.A town has 47300 people. The population grows by 5% every year. What will the population be after 1 year?
30. 30.Find the compound interest on ₹41000 at 10% per year for 3 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹57100 at 5% per year for 1 year, compounded every year (in ₹).
32. 32.A scooter is worth ₹37600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
33. 33.What amount will ₹53200 grow to in 2 years at 25% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹31300 at 10% per year for 2 years (in ₹)?
35. 35.What amount will ₹4900 grow to in 2 years at 10% per year compound interest (in ₹)?
36. 36.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
37. 37.A scooter is worth ₹13600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹32000 at 5% per year for 2 years (in ₹)?
40. 40.A town has 50000 people. The population grows by 8% every year. What will the population be after 2 years?

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