Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 885 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹15900 at 20% per year for 2 years, compounded every year (in ₹).
2. 2.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
3. 3.A town has 35400 people. The population grows by 10% every year. What will the population be after 2 years?
4. 4.What amount will ₹43700 grow to in 1 year at 12% per year compound interest (in ₹)?
5. 5.What amount will ₹38800 grow to in 1 year at 20% per year compound interest (in ₹)?
6. 6.A scooter is worth ₹37500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹48900 at 20% per year for 2 years (in ₹)?
8. 8.What amount will ₹59100 grow to in 1 year at 20% per year compound interest (in ₹)?
9. 9.What amount will ₹10400 grow to in 1 year at 8% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹46000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
11. 11.Find the compound interest on ₹19200 at 20% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹35600 at 5% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹58100 at 20% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
17. 17.What amount will ₹6400 grow to in 1 year at 15% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹47200 at 20% per year for 1 year, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹2400 at 5% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹21200 at 5% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹2300 at 12% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹53600 at 5% per year for 1 year, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹24000 at 20% per year for 2 years (in ₹)?
28. 28.What amount will ₹8000 grow to in 1 year at 12% per year compound interest (in ₹)?
29. 29.A town has 53300 people. The population grows by 10% every year. What will the population be after 1 year?
30. 30.Find the compound interest on ₹22100 at 12% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹48800 at 25% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹24200 at 15% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹43000 grow to in 3 years at 20% per year compound interest (in ₹)?
34. 34.A town has 34000 people. The population grows by 10% every year. What will the population be after 1 year?
35. 35.What amount will ₹45000 grow to in 3 years at 10% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹18800 at 5% per year for 2 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
38. 38.A town has 14800 people. The population grows by 25% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹21500 at 20% per year for 3 years, compounded every year (in ₹).
40. 40.A town has 37500 people. The population grows by 4% every year. What will the population be after 2 years?

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