Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 888 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
2. 2.What amount will ₹32400 grow to in 1 year at 20% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
4. 4.What amount will ₹45000 grow to in 3 years at 10% per year compound interest (in ₹)?
5. 5.What amount will ₹48200 grow to in 1 year at 25% per year compound interest (in ₹)?
6. 6.What amount will ₹29200 grow to in 2 years at 5% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹54800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
8. 8.A town has 30000 people. The population grows by 5% every year. What will the population be after 2 years?
9. 9.What amount will ₹4000 grow to in 3 years at 10% per year compound interest (in ₹)?
10. 10.What amount will ₹26600 grow to in 1 year at 4% per year compound interest (in ₹)?
11. 11.What amount will ₹4800 grow to in 1 year at 8% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
13. 13.A town has 54400 people. The population grows by 10% every year. What will the population be after 2 years?
14. 14.What is the difference between the compound interest and the simple interest on ₹52000 at 10% per year for 2 years (in ₹)?
15. 15.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹11000 at 10% per year for 3 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹28400 at 25% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹44000 at 20% per year for 3 years, compounded every year (in ₹).
19. 19.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
20. 20.A town has 44000 people. The population grows by 5% every year. What will the population be after 2 years?
21. 21.What amount will ₹15000 grow to in 2 years at 8% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹28000 at 5% per year for 2 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹4700 at 20% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹52200 at 10% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹57500 at 12% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹29600 grow to in 1 year at 10% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹36800 at 5% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹47800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
30. 30.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
31. 31.What amount will ₹32700 grow to in 1 year at 12% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹51200 at 5% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹11500 at 10% per year for 2 years, compounded every year (in ₹).
34. 34.What amount will ₹11600 grow to in 2 years at 15% per year compound interest (in ₹)?
35. 35.A scooter is worth ₹22400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
36. 36.A town has 9200 people. The population grows by 10% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹18000 at 5% per year for 2 years (in ₹)?
39. 39.What amount will ₹31900 grow to in 1 year at 10% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹15500 at 20% per year for 3 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets