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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 891 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
  2. 2.What amount will ₹56900 grow to in 2 years at 10% per year compound interest (in ₹)?
  3. 3.A town has 12400 people. The population grows by 25% every year. What will the population be after 2 years?
  4. 4.A town has 8000 people. The population grows by 25% every year. What will the population be after 3 years?
  5. 5.A scooter is worth ₹49400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹22300 at 10% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹47600 at 4% per year for 1 year, compounded every year (in ₹).
  9. 9.A town has 42800 people. The population grows by 5% every year. What will the population be after 2 years?
  10. 10.What amount will ₹14800 grow to in 1 year at 5% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹29400 at 10% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹51200 at 15% per year for 1 year, compounded every year (in ₹).
  14. 14.A town has 40100 people. The population grows by 4% every year. What will the population be after 1 year?
  15. 15.Find the compound interest on ₹4000 at 20% per year for 3 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹15400 at 8% per year for 1 year, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹8100 at 20% per year for 2 years (in ₹)?
  18. 18.What amount will ₹17000 grow to in 3 years at 20% per year compound interest (in ₹)?
  19. 19.A town has 25200 people. The population grows by 15% every year. What will the population be after 1 year?
  20. 20.A scooter is worth ₹55200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  21. 21.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  22. 22.What amount will ₹52800 grow to in 3 years at 25% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹3600 at 5% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
  25. 25.A town has 8300 people. The population grows by 4% every year. What will the population be after 1 year?
  26. 26.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹30700 at 4% per year for 1 year, compounded every year (in ₹).
  28. 28.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  29. 29.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹32400 at 5% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹5000 at 20% per year for 3 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹32000 at 5% per year for 2 years, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  34. 34.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
  35. 35.What amount will ₹49600 grow to in 2 years at 15% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹46000 at 25% per year for 2 years (in ₹)?
  37. 37.What amount will ₹31200 grow to in 2 years at 5% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).
  39. 39.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
  40. 40.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?

Answer key

  1. 8320
  2. 68849
  3. 19375
  4. 15625
  5. 41990
  6. 223
  7. 2522
  8. 1904
  9. 47187
  10. 15540
  11. 294
  12. 2448
  13. 7680
  14. 41704
  15. 2912
  16. 1232
  17. 324
  18. 29376
  19. 28980
  20. 31050
  21. 25168
  22. 103125
  23. 369
  24. 8736
  25. 8632
  26. 61
  27. 1228
  28. 64827
  29. 18522
  30. 81
  31. 3640
  32. 3280
  33. 6305
  34. 112
  35. 65596
  36. 2875
  37. 34398
  38. 1324
  39. 35152
  40. 65856

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