Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
- 2.What amount will ₹56900 grow to in 2 years at 10% per year compound interest (in ₹)?
- 3.A town has 12400 people. The population grows by 25% every year. What will the population be after 2 years?
- 4.A town has 8000 people. The population grows by 25% every year. What will the population be after 3 years?
- 5.A scooter is worth ₹49400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹22300 at 10% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 8.Find the compound interest on ₹47600 at 4% per year for 1 year, compounded every year (in ₹).
- 9.A town has 42800 people. The population grows by 5% every year. What will the population be after 2 years?
- 10.What amount will ₹14800 grow to in 1 year at 5% per year compound interest (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹29400 at 10% per year for 2 years (in ₹)?
- 12.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹51200 at 15% per year for 1 year, compounded every year (in ₹).
- 14.A town has 40100 people. The population grows by 4% every year. What will the population be after 1 year?
- 15.Find the compound interest on ₹4000 at 20% per year for 3 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹15400 at 8% per year for 1 year, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹8100 at 20% per year for 2 years (in ₹)?
- 18.What amount will ₹17000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 19.A town has 25200 people. The population grows by 15% every year. What will the population be after 1 year?
- 20.A scooter is worth ₹55200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 21.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 22.What amount will ₹52800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹3600 at 5% per year for 2 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
- 25.A town has 8300 people. The population grows by 4% every year. What will the population be after 1 year?
- 26.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹30700 at 4% per year for 1 year, compounded every year (in ₹).
- 28.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 29.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹32400 at 5% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹5000 at 20% per year for 3 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹32000 at 5% per year for 2 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
- 35.What amount will ₹49600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹46000 at 25% per year for 2 years (in ₹)?
- 37.What amount will ₹31200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).
- 39.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
- 40.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
Answer key
- 8320
- 68849
- 19375
- 15625
- 41990
- 223
- 2522
- 1904
- 47187
- 15540
- 294
- 2448
- 7680
- 41704
- 2912
- 1232
- 324
- 29376
- 28980
- 31050
- 25168
- 103125
- 369
- 8736
- 8632
- 61
- 1228
- 64827
- 18522
- 81
- 3640
- 3280
- 6305
- 112
- 65596
- 2875
- 34398
- 1324
- 35152
- 65856
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