Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹43000 at 10% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹51600 at 25% per year for 2 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
- 6.What is the difference between the compound interest and the simple interest on ₹38600 at 10% per year for 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹25600 at 25% per year for 2 years (in ₹)?
- 8.A town has 24200 people. The population grows by 4% every year. What will the population be after 1 year?
- 9.A town has 30400 people. The population grows by 25% every year. What will the population be after 1 year?
- 10.What is the difference between the compound interest and the simple interest on ₹8800 at 5% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹59200 at 25% per year for 2 years, compounded every year (in ₹).
- 12.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 13.Find the compound interest on ₹2900 at 10% per year for 1 year, compounded every year (in ₹).
- 14.Find the compound interest on ₹6400 at 10% per year for 1 year, compounded every year (in ₹).
- 15.Find the compound interest on ₹9900 at 20% per year for 2 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹14000 at 25% per year for 2 years, compounded every year (in ₹).
- 17.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 18.Find the compound interest on ₹6900 at 20% per year for 1 year, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹22500 at 20% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹35300 at 10% per year for 2 years, compounded every year (in ₹).
- 21.Find the compound interest on ₹40400 at 12% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹13600 at 5% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹43300 at 10% per year for 1 year, compounded every year (in ₹).
- 24.A scooter is worth ₹36000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹2000 at 15% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹7600 at 5% per year for 2 years (in ₹)?
- 28.A scooter is worth ₹48900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 29.What amount will ₹21600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 30.A town has 28800 people. The population grows by 20% every year. What will the population be after 1 year?
- 31.A town has 35500 people. The population grows by 20% every year. What will the population be after 2 years?
- 32.What amount will ₹5200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 33.What amount will ₹10400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
- 36.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹40200 at 10% per year for 2 years, compounded every year (in ₹).
- 38.What amount will ₹11600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 39.What amount will ₹12500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 40.What amount will ₹19700 grow to in 1 year at 12% per year compound interest (in ₹)?
Answer key
- 14739
- 430
- 16
- 29025
- 7072
- 386
- 1600
- 25168
- 38000
- 22
- 33300
- 24565
- 290
- 640
- 4356
- 7875
- 18522
- 1380
- 900
- 7413
- 4848
- 34
- 4330
- 34200
- 45
- 204
- 19
- 41565
- 26136
- 34560
- 51120
- 6877
- 11466
- 224
- 21350
- 8748
- 8442
- 15341
- 13520
- 22064
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