Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 899 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹35000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
2. 2.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 3400 people. The population grows by 8% every year. What will the population be after 1 year?
6. 6.What is the difference between the compound interest and the simple interest on ₹34000 at 25% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹12400 at 5% per year for 2 years (in ₹)?
8. 8.What amount will ₹7400 grow to in 1 year at 12% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹3200 at 25% per year for 2 years, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹54200 at 10% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹24300 at 25% per year for 1 year, compounded every year (in ₹).
12. 12.A town has 60000 people. The population grows by 8% every year. What will the population be after 2 years?
13. 13.What amount will ₹15000 grow to in 3 years at 20% per year compound interest (in ₹)?
14. 14.A town has 56000 people. The population grows by 25% every year. What will the population be after 3 years?
15. 15.Find the compound interest on ₹40000 at 10% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹46500 at 20% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
20. 20.A scooter is worth ₹10900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
21. 21.Find the compound interest on ₹33200 at 8% per year for 1 year, compounded every year (in ₹).
22. 22.Find the compound interest on ₹31400 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.A town has 27100 people. The population grows by 4% every year. What will the population be after 1 year?
24. 24.What is the difference between the compound interest and the simple interest on ₹40300 at 20% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹19200 at 15% per year for 2 years (in ₹)?
26. 26.What amount will ₹38800 grow to in 2 years at 15% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹40800 at 5% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
29. 29.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
30. 30.A town has 2000 people. The population grows by 25% every year. What will the population be after 1 year?
31. 31.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹40500 at 5% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹5700 grow to in 1 year at 10% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹5000 at 4% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
37. 37.What amount will ₹17500 grow to in 3 years at 20% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹50200 at 10% per year for 2 years (in ₹)?
39. 39.What amount will ₹59200 grow to in 3 years at 25% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹56800 at 25% per year for 1 year, compounded every year (in ₹).

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