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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 903 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹47500 grow to in 3 years at 20% per year compound interest (in ₹)?
  2. 2.What amount will ₹7000 grow to in 2 years at 20% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹13200 at 10% per year for 2 years, compounded every year (in ₹).
  5. 5.What amount will ₹48700 grow to in 1 year at 12% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹54900 at 20% per year for 2 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹6400 at 25% per year for 2 years (in ₹)?
  8. 8.A town has 46100 people. The population grows by 12% every year. What will the population be after 1 year?
  9. 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  10. 10.A scooter is worth ₹27800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  11. 11.What amount will ₹57200 grow to in 2 years at 20% per year compound interest (in ₹)?
  12. 12.A scooter is worth ₹7300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  13. 13.What amount will ₹47500 grow to in 1 year at 8% per year compound interest (in ₹)?
  14. 14.A town has 7000 people. The population grows by 5% every year. What will the population be after 1 year?
  15. 15.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
  16. 16.What amount will ₹20400 grow to in 1 year at 10% per year compound interest (in ₹)?
  17. 17.A town has 52000 people. The population grows by 5% every year. What will the population be after 2 years?
  18. 18.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  19. 19.A scooter is worth ₹49500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  20. 20.Find the compound interest on ₹29000 at 10% per year for 3 years, compounded every year (in ₹).
  21. 21.A town has 4200 people. The population grows by 20% every year. What will the population be after 2 years?
  22. 22.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  23. 23.What amount will ₹14000 grow to in 3 years at 20% per year compound interest (in ₹)?
  24. 24.A town has 28300 people. The population grows by 20% every year. What will the population be after 2 years?
  25. 25.Find the compound interest on ₹22300 at 25% per year for 1 year, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  27. 27.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  28. 28.A town has 42900 people. The population grows by 12% every year. What will the population be after 1 year?
  29. 29.A town has 2500 people. The population grows by 20% every year. What will the population be after 3 years?
  30. 30.Find the compound interest on ₹53900 at 4% per year for 1 year, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹50800 at 25% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
  35. 35.A scooter is worth ₹26000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  36. 36.A scooter is worth ₹38000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  37. 37.Find the compound interest on ₹51300 at 10% per year for 2 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
  39. 39.A town has 46500 people. The population grows by 20% every year. What will the population be after 3 years?
  40. 40.What is the difference between the compound interest and the simple interest on ₹14400 at 15% per year for 2 years (in ₹)?

Answer key

  1. 82080
  2. 10080
  3. 60
  4. 2772
  5. 54544
  6. 24156
  7. 400
  8. 51632
  9. 9261
  10. 20850
  11. 82368
  12. 5913
  13. 51300
  14. 7350
  15. 16775
  16. 22440
  17. 57330
  18. 576
  19. 43560
  20. 9599
  21. 6048
  22. 336
  23. 24192
  24. 40752
  25. 5575
  26. 864
  27. 12167
  28. 48048
  29. 4320
  30. 2156
  31. 4576
  32. 28575
  33. 720
  34. 2025
  35. 18954
  36. 19456
  37. 10773
  38. 17874
  39. 80352
  40. 324

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