Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹47500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 2.What amount will ₹7000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹13200 at 10% per year for 2 years, compounded every year (in ₹).
- 5.What amount will ₹48700 grow to in 1 year at 12% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹54900 at 20% per year for 2 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹6400 at 25% per year for 2 years (in ₹)?
- 8.A town has 46100 people. The population grows by 12% every year. What will the population be after 1 year?
- 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 10.A scooter is worth ₹27800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 11.What amount will ₹57200 grow to in 2 years at 20% per year compound interest (in ₹)?
- 12.A scooter is worth ₹7300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 13.What amount will ₹47500 grow to in 1 year at 8% per year compound interest (in ₹)?
- 14.A town has 7000 people. The population grows by 5% every year. What will the population be after 1 year?
- 15.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
- 16.What amount will ₹20400 grow to in 1 year at 10% per year compound interest (in ₹)?
- 17.A town has 52000 people. The population grows by 5% every year. What will the population be after 2 years?
- 18.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 19.A scooter is worth ₹49500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 20.Find the compound interest on ₹29000 at 10% per year for 3 years, compounded every year (in ₹).
- 21.A town has 4200 people. The population grows by 20% every year. What will the population be after 2 years?
- 22.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 23.What amount will ₹14000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 24.A town has 28300 people. The population grows by 20% every year. What will the population be after 2 years?
- 25.Find the compound interest on ₹22300 at 25% per year for 1 year, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
- 27.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 28.A town has 42900 people. The population grows by 12% every year. What will the population be after 1 year?
- 29.A town has 2500 people. The population grows by 20% every year. What will the population be after 3 years?
- 30.Find the compound interest on ₹53900 at 4% per year for 1 year, compounded every year (in ₹).
- 31.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹50800 at 25% per year for 2 years, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
- 35.A scooter is worth ₹26000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 36.A scooter is worth ₹38000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 37.Find the compound interest on ₹51300 at 10% per year for 2 years, compounded every year (in ₹).
- 38.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
- 39.A town has 46500 people. The population grows by 20% every year. What will the population be after 3 years?
- 40.What is the difference between the compound interest and the simple interest on ₹14400 at 15% per year for 2 years (in ₹)?
Answer key
- 82080
- 10080
- 60
- 2772
- 54544
- 24156
- 400
- 51632
- 9261
- 20850
- 82368
- 5913
- 51300
- 7350
- 16775
- 22440
- 57330
- 576
- 43560
- 9599
- 6048
- 336
- 24192
- 40752
- 5575
- 864
- 12167
- 48048
- 4320
- 2156
- 4576
- 28575
- 720
- 2025
- 18954
- 19456
- 10773
- 17874
- 80352
- 324
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