Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 907 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 50000 people. The population grows by 4% every year. What will the population be after 2 years?
2. 2.A town has 34500 people. The population grows by 4% every year. What will the population be after 1 year?
3. 3.A scooter is worth ₹18900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
4. 4.Find the compound interest on ₹59300 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹56000 at 25% per year for 2 years (in ₹)?
7. 7.A town has 56300 people. The population grows by 20% every year. What will the population be after 2 years?
8. 8.A town has 44000 people. The population grows by 5% every year. What will the population be after 2 years?
9. 9.What amount will ₹23600 grow to in 1 year at 4% per year compound interest (in ₹)?
10. 10.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹55600 at 25% per year for 2 years (in ₹)?
12. 12.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹18000 at 20% per year for 3 years, compounded every year (in ₹).
15. 15.A town has 35200 people. The population grows by 15% every year. What will the population be after 2 years?
16. 16.What amount will ₹14500 grow to in 1 year at 12% per year compound interest (in ₹)?
17. 17.What amount will ₹59300 grow to in 2 years at 10% per year compound interest (in ₹)?
18. 18.What amount will ₹25500 grow to in 1 year at 10% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹9100 at 5% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
21. 21.A town has 8600 people. The population grows by 4% every year. What will the population be after 1 year?
22. 22.What is the difference between the compound interest and the simple interest on ₹30400 at 15% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹10000 at 25% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹5400 at 5% per year for 1 year, compounded every year (in ₹).
25. 25.A scooter is worth ₹30300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹5600 at 10% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹30000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
30. 30.Find the compound interest on ₹16000 at 10% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹32800 grow to in 1 year at 4% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹36400 at 15% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹55700 at 25% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
35. 35.A town has 31900 people. The population grows by 25% every year. What will the population be after 1 year?
36. 36.Find the compound interest on ₹4600 at 10% per year for 2 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹60000 at 10% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹51500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
39. 39.A town has 6400 people. The population grows by 5% every year. What will the population be after 1 year?
40. 40.What amount will ₹35200 grow to in 2 years at 25% per year compound interest (in ₹)?

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