Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 91 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹52000 at 8% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹26000 at 5% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
4. 4.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
5. 5.Find the compound interest on ₹9100 at 10% per year for 1 year, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
7. 7.A town has 52100 people. The population grows by 25% every year. What will the population be after 1 year?
8. 8.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹50400 at 25% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹59700 at 10% per year for 1 year, compounded every year (in ₹).
11. 11.What amount will ₹9000 grow to in 3 years at 10% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹38400 at 20% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹36800 at 10% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
16. 16.What amount will ₹14700 grow to in 2 years at 20% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹15500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
18. 18.A town has 26000 people. The population grows by 10% every year. What will the population be after 3 years?
19. 19.Find the compound interest on ₹50000 at 5% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹2100 at 20% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹47500 at 20% per year for 2 years, compounded every year (in ₹).
22. 22.A town has 44500 people. The population grows by 10% every year. What will the population be after 1 year?
23. 23.A town has 37500 people. The population grows by 12% every year. What will the population be after 1 year?
24. 24.A town has 47200 people. The population grows by 15% every year. What will the population be after 2 years?
25. 25.A town has 6900 people. The population grows by 15% every year. What will the population be after 1 year?
26. 26.Find the compound interest on ₹12700 at 8% per year for 1 year, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹29900 at 20% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
29. 29.What amount will ₹40000 grow to in 2 years at 12% per year compound interest (in ₹)?
30. 30.What amount will ₹54500 grow to in 2 years at 10% per year compound interest (in ₹)?
31. 31.What amount will ₹36900 grow to in 1 year at 15% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹18900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
33. 33.Find the compound interest on ₹15400 at 15% per year for 1 year, compounded every year (in ₹).
34. 34.A scooter is worth ₹13900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
35. 35.Find the compound interest on ₹29600 at 25% per year for 2 years, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
37. 37.A town has 46000 people. The population grows by 8% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹47900 at 10% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹5200 at 5% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹10000 at 25% per year for 2 years (in ₹)?

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