Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 913 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹5600 at 20% per year for 2 years, compounded every year (in ₹).
2. 2.A town has 27100 people. The population grows by 15% every year. What will the population be after 1 year?
3. 3.A town has 58100 people. The population grows by 4% every year. What will the population be after 1 year?
4. 4.What amount will ₹17500 grow to in 2 years at 12% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹49700 at 10% per year for 2 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹36400 at 10% per year for 1 year, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
9. 9.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹18800 at 20% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹50000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
13. 13.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
14. 14.A town has 15000 people. The population grows by 10% every year. What will the population be after 3 years?
15. 15.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
19. 19.What amount will ₹2000 grow to in 1 year at 10% per year compound interest (in ₹)?
20. 20.What amount will ₹16800 grow to in 2 years at 15% per year compound interest (in ₹)?
21. 21.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
22. 22.Find the compound interest on ₹9600 at 25% per year for 1 year, compounded every year (in ₹).
23. 23.What amount will ₹20600 grow to in 1 year at 10% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹27500 at 20% per year for 3 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹7600 at 15% per year for 2 years (in ₹)?
26. 26.What amount will ₹33700 grow to in 1 year at 20% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹6000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
28. 28.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
30. 30.A town has 58400 people. The population grows by 5% every year. What will the population be after 2 years?
31. 31.A town has 59900 people. The population grows by 4% every year. What will the population be after 1 year?
32. 32.What amount will ₹57700 grow to in 1 year at 15% per year compound interest (in ₹)?
33. 33.What amount will ₹59600 grow to in 1 year at 25% per year compound interest (in ₹)?
34. 34.What amount will ₹22200 grow to in 1 year at 25% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹51600 at 8% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹32600 at 20% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹28400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
39. 39.A town has 44800 people. The population grows by 25% every year. What will the population be after 3 years?
40. 40.What is the difference between the compound interest and the simple interest on ₹13000 at 10% per year for 2 years (in ₹)?

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