Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 915 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹20600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
2. 2.A scooter is worth ₹14400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹55100 at 12% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹27200 at 8% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹14400 at 25% per year for 2 years, compounded every year (in ₹).
7. 7.A town has 15700 people. The population grows by 8% every year. What will the population be after 1 year?
8. 8.What is the difference between the compound interest and the simple interest on ₹10000 at 25% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹30900 at 20% per year for 1 year, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹53600 at 5% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹44400 at 15% per year for 2 years (in ₹)?
13. 13.What amount will ₹18500 grow to in 1 year at 20% per year compound interest (in ₹)?
14. 14.A scooter is worth ₹11200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹20000 at 5% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
17. 17.A scooter is worth ₹24800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹13800 at 20% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹46500 at 10% per year for 2 years (in ₹)?
21. 21.What amount will ₹14700 grow to in 1 year at 12% per year compound interest (in ₹)?
22. 22.A town has 27400 people. The population grows by 10% every year. What will the population be after 1 year?
23. 23.Find the compound interest on ₹57600 at 20% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹31000 grow to in 3 years at 20% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹16000 at 15% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹31400 at 20% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹34600 at 20% per year for 2 years (in ₹)?
29. 29.What amount will ₹55500 grow to in 3 years at 20% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹52600 at 5% per year for 1 year, compounded every year (in ₹).
31. 31.A town has 7200 people. The population grows by 5% every year. What will the population be after 2 years?
32. 32.What amount will ₹20800 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹35200 at 5% per year for 2 years (in ₹)?
34. 34.What amount will ₹26600 grow to in 1 year at 12% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹40800 at 25% per year for 2 years, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
37. 37.A town has 13000 people. The population grows by 12% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹49500 at 10% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹58000 at 20% per year for 3 years, compounded every year (in ₹).
40. 40.What amount will ₹23000 grow to in 3 years at 20% per year compound interest (in ₹)?

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