Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 919 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹30400 grow to in 3 years at 25% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹4000 at 12% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹24200 at 10% per year for 2 years (in ₹)?
6. 6.A scooter is worth ₹27900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹59500 at 15% per year for 1 year, compounded every year (in ₹).
9. 9.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
10. 10.A scooter is worth ₹26100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹42100 at 10% per year for 2 years (in ₹)?
12. 12.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
13. 13.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
14. 14.What amount will ₹46100 grow to in 1 year at 15% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹57500 at 4% per year for 2 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹49200 at 25% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹13200 at 15% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹23000 at 20% per year for 2 years (in ₹)?
19. 19.What amount will ₹17300 grow to in 2 years at 10% per year compound interest (in ₹)?
20. 20.A town has 19900 people. The population grows by 8% every year. What will the population be after 1 year?
21. 21.What amount will ₹52800 grow to in 1 year at 25% per year compound interest (in ₹)?
22. 22.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
23. 23.Find the compound interest on ₹16900 at 8% per year for 1 year, compounded every year (in ₹).
24. 24.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
25. 25.Find the compound interest on ₹31400 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹26500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹10000 at 15% per year for 2 years, compounded every year (in ₹).
29. 29.A town has 40000 people. The population grows by 4% every year. What will the population be after 2 years?
30. 30.Find the compound interest on ₹29600 at 25% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹29200 grow to in 2 years at 5% per year compound interest (in ₹)?
32. 32.What amount will ₹7600 grow to in 2 years at 5% per year compound interest (in ₹)?
33. 33.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
35. 35.A town has 16600 people. The population grows by 12% every year. What will the population be after 1 year?
36. 36.Find the compound interest on ₹48000 at 5% per year for 2 years, compounded every year (in ₹).
37. 37.A scooter is worth ₹11000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹7600 at 25% per year for 2 years (in ₹)?
39. 39.What amount will ₹33300 grow to in 2 years at 20% per year compound interest (in ₹)?
40. 40.A scooter is worth ₹52600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?

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