← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 924 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹32000 at 10% per year for 3 years, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹20400 at 25% per year for 1 year, compounded every year (in ₹).
  3. 3.A scooter is worth ₹2100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  4. 4.A scooter is worth ₹48000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  6. 6.A town has 26400 people. The population grows by 12% every year. What will the population be after 1 year?
  7. 7.Find the compound interest on ₹3100 at 4% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹40000 at 10% per year for 3 years, compounded every year (in ₹).
  9. 9.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
  10. 10.A town has 43600 people. The population grows by 25% every year. What will the population be after 1 year?
  11. 11.Find the compound interest on ₹14400 at 25% per year for 2 years, compounded every year (in ₹).
  12. 12.A town has 23700 people. The population grows by 10% every year. What will the population be after 2 years?
  13. 13.Find the compound interest on ₹35300 at 12% per year for 1 year, compounded every year (in ₹).
  14. 14.A scooter is worth ₹5300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  15. 15.A town has 25000 people. The population grows by 4% every year. What will the population be after 2 years?
  16. 16.What amount will ₹54800 grow to in 2 years at 25% per year compound interest (in ₹)?
  17. 17.What amount will ₹24200 grow to in 2 years at 10% per year compound interest (in ₹)?
  18. 18.What amount will ₹27500 grow to in 2 years at 20% per year compound interest (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹24600 at 20% per year for 2 years (in ₹)?
  21. 21.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  22. 22.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
  23. 23.What amount will ₹44100 grow to in 1 year at 8% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹23200 at 15% per year for 2 years (in ₹)?
  25. 25.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
  26. 26.Find the compound interest on ₹23600 at 5% per year for 2 years, compounded every year (in ₹).
  27. 27.What amount will ₹36100 grow to in 1 year at 8% per year compound interest (in ₹)?
  28. 28.What amount will ₹8000 grow to in 2 years at 5% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹3900 at 12% per year for 1 year, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹38600 at 8% per year for 1 year, compounded every year (in ₹).
  31. 31.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
  32. 32.Find the compound interest on ₹19300 at 20% per year for 1 year, compounded every year (in ₹).
  33. 33.What amount will ₹47500 grow to in 3 years at 20% per year compound interest (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹37100 at 10% per year for 2 years (in ₹)?
  35. 35.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
  36. 36.What amount will ₹31200 grow to in 2 years at 10% per year compound interest (in ₹)?
  37. 37.A town has 7700 people. The population grows by 15% every year. What will the population be after 1 year?
  38. 38.Find the compound interest on ₹28300 at 5% per year for 1 year, compounded every year (in ₹).
  39. 39.A town has 22300 people. The population grows by 12% every year. What will the population be after 1 year?
  40. 40.A scooter is worth ₹52000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 10592
  2. 5100
  3. 1701
  4. 42240
  5. 28
  6. 29568
  7. 124
  8. 13240
  9. 27783
  10. 54500
  11. 8100
  12. 28677
  13. 4236
  14. 5035
  15. 27040
  16. 85625
  17. 29282
  18. 39600
  19. 141
  20. 984
  21. 9261
  22. 34992
  23. 47628
  24. 522
  25. 55404
  26. 2419
  27. 38988
  28. 8820
  29. 468
  30. 3088
  31. 36501
  32. 3860
  33. 82080
  34. 371
  35. 60835
  36. 37752
  37. 8855
  38. 1415
  39. 24976
  40. 47840

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets