Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 926 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
2. 2.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹17600 at 5% per year for 1 year, compounded every year (in ₹).
5. 5.Find the compound interest on ₹8300 at 25% per year for 1 year, compounded every year (in ₹).
6. 6.What amount will ₹39500 grow to in 1 year at 15% per year compound interest (in ₹)?
7. 7.A town has 48600 people. The population grows by 10% every year. What will the population be after 2 years?
8. 8.What is the difference between the compound interest and the simple interest on ₹56800 at 5% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
10. 10.A scooter is worth ₹30000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
11. 11.A scooter is worth ₹54600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
12. 12.Find the compound interest on ₹41200 at 15% per year for 2 years, compounded every year (in ₹).
13. 13.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
14. 14.What amount will ₹44600 grow to in 1 year at 8% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹56000 at 25% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹10600 grow to in 1 year at 25% per year compound interest (in ₹)?
17. 17.What amount will ₹26000 grow to in 2 years at 5% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹27100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
20. 20.What amount will ₹56000 grow to in 3 years at 20% per year compound interest (in ₹)?
21. 21.A town has 40100 people. The population grows by 25% every year. What will the population be after 1 year?
22. 22.Find the compound interest on ₹54100 at 8% per year for 1 year, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹47300 at 20% per year for 2 years (in ₹)?
24. 24.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
25. 25.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
26. 26.What amount will ₹35600 grow to in 2 years at 15% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
28. 28.What amount will ₹11300 grow to in 1 year at 10% per year compound interest (in ₹)?
29. 29.A town has 25000 people. The population grows by 12% every year. What will the population be after 2 years?
30. 30.What is the difference between the compound interest and the simple interest on ₹55200 at 5% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹47600 at 8% per year for 1 year, compounded every year (in ₹).
32. 32.A town has 32100 people. The population grows by 5% every year. What will the population be after 1 year?
33. 33.What is the difference between the compound interest and the simple interest on ₹34400 at 25% per year for 2 years (in ₹)?
34. 34.What amount will ₹41900 grow to in 2 years at 10% per year compound interest (in ₹)?
35. 35.What amount will ₹17200 grow to in 2 years at 25% per year compound interest (in ₹)?
36. 36.A scooter is worth ₹19200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
37. 37.Find the compound interest on ₹40500 at 20% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
39. 39.A town has 17300 people. The population grows by 10% every year. What will the population be after 1 year?
40. 40.What amount will ₹9400 grow to in 1 year at 20% per year compound interest (in ₹)?

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