Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 2.A scooter is worth ₹43200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 3.Find the compound interest on ₹24300 at 5% per year for 1 year, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹15200 at 15% per year for 2 years (in ₹)?
- 5.What amount will ₹33600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹12800 at 15% per year for 2 years, compounded every year (in ₹).
- 7.A town has 17300 people. The population grows by 5% every year. What will the population be after 1 year?
- 8.What amount will ₹50400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹36100 at 10% per year for 2 years, compounded every year (in ₹).
- 10.Find the compound interest on ₹28100 at 10% per year for 2 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹56700 at 12% per year for 1 year, compounded every year (in ₹).
- 12.A scooter is worth ₹42500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 13.What amount will ₹40900 grow to in 2 years at 20% per year compound interest (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹11600 at 25% per year for 2 years (in ₹)?
- 15.What amount will ₹43800 grow to in 1 year at 8% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹2800 at 10% per year for 2 years (in ₹)?
- 17.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
- 20.A scooter is worth ₹59800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 21.A scooter is worth ₹32500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹16900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 24.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹13600 at 20% per year for 1 year, compounded every year (in ₹).
- 26.A town has 47500 people. The population grows by 20% every year. What will the population be after 3 years?
- 27.What is the difference between the compound interest and the simple interest on ₹5200 at 5% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹18600 at 8% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹6400 at 20% per year for 1 year, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹41200 at 15% per year for 2 years (in ₹)?
- 31.What amount will ₹36800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 32.A scooter is worth ₹24200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 33.Find the compound interest on ₹27600 at 5% per year for 1 year, compounded every year (in ₹).
- 34.A town has 15200 people. The population grows by 15% every year. What will the population be after 2 years?
- 35.What amount will ₹54300 grow to in 2 years at 10% per year compound interest (in ₹)?
- 36.A scooter is worth ₹19100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 37.Find the compound interest on ₹53300 at 15% per year for 1 year, compounded every year (in ₹).
- 38.A town has 3900 people. The population grows by 20% every year. What will the population be after 2 years?
- 39.What amount will ₹2500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹58800 at 12% per year for 1 year, compounded every year (in ₹).
Answer key
- 8334
- 18225
- 1215
- 342
- 52500
- 4128
- 18165
- 55566
- 7581
- 5901
- 6804
- 39168
- 58896
- 725
- 47304
- 28
- 12167
- 51850
- 84
- 56810
- 16640
- 32
- 15548
- 4488
- 2720
- 82080
- 13
- 1488
- 1280
- 927
- 40572
- 19602
- 1380
- 20102
- 65703
- 18336
- 7995
- 5616
- 2750
- 7056
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