← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 932 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹33400 at 20% per year for 2 years (in ₹)?
  2. 2.A town has 54100 people. The population grows by 20% every year. What will the population be after 2 years?
  3. 3.What is the difference between the compound interest and the simple interest on ₹28500 at 10% per year for 2 years (in ₹)?
  4. 4.What amount will ₹21200 grow to in 2 years at 10% per year compound interest (in ₹)?
  5. 5.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹49300 at 10% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹16400 at 10% per year for 2 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹47600 at 15% per year for 1 year, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹36000 at 10% per year for 3 years, compounded every year (in ₹).
  11. 11.A town has 32500 people. The population grows by 8% every year. What will the population be after 2 years?
  12. 12.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
  13. 13.A town has 37200 people. The population grows by 15% every year. What will the population be after 2 years?
  14. 14.Find the compound interest on ₹38000 at 10% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹48900 at 10% per year for 1 year, compounded every year (in ₹).
  17. 17.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹13000 at 4% per year for 1 year, compounded every year (in ₹).
  19. 19.A scooter is worth ₹56400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  20. 20.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  23. 23.What amount will ₹16400 grow to in 2 years at 5% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹10400 at 15% per year for 2 years, compounded every year (in ₹).
  26. 26.A town has 41000 people. The population grows by 10% every year. What will the population be after 1 year?
  27. 27.What is the difference between the compound interest and the simple interest on ₹50700 at 20% per year for 2 years (in ₹)?
  28. 28.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  29. 29.What amount will ₹40000 grow to in 2 years at 8% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  31. 31.What amount will ₹51700 grow to in 1 year at 15% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹43200 at 5% per year for 2 years (in ₹)?
  33. 33.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  34. 34.What amount will ₹14800 grow to in 2 years at 10% per year compound interest (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹31200 at 25% per year for 2 years (in ₹)?
  37. 37.What amount will ₹50800 grow to in 2 years at 5% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹13600 at 5% per year for 2 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
  40. 40.What amount will ₹48200 grow to in 1 year at 15% per year compound interest (in ₹)?

Answer key

  1. 1336
  2. 77904
  3. 285
  4. 25652
  5. 40768
  6. 493
  7. 3444
  8. 7140
  9. 816
  10. 11916
  11. 37908
  12. 2704
  13. 49197
  14. 3800
  15. 20835
  16. 4890
  17. 11664
  18. 520
  19. 40749
  20. 8827
  21. 576
  22. 336
  23. 18081
  24. 3310
  25. 3354
  26. 45100
  27. 2028
  28. 55566
  29. 46656
  30. 12
  31. 59455
  32. 108
  33. 19044
  34. 17908
  35. 56
  36. 1950
  37. 56007
  38. 1394
  39. 4576
  40. 55430

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets