Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.A scooter is worth ₹15500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 2.What amount will ₹14700 grow to in 1 year at 25% per year compound interest (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹20900 at 10% per year for 2 years (in ₹)?
- 4.A town has 13000 people. The population grows by 20% every year. What will the population be after 3 years?
- 5.Find the compound interest on ₹8000 at 4% per year for 1 year, compounded every year (in ₹).
- 6.A town has 38000 people. The population grows by 5% every year. What will the population be after 1 year?
- 7.Find the compound interest on ₹51200 at 8% per year for 1 year, compounded every year (in ₹).
- 8.A town has 7500 people. The population grows by 4% every year. What will the population be after 2 years?
- 9.Find the compound interest on ₹54800 at 15% per year for 2 years, compounded every year (in ₹).
- 10.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹18800 at 15% per year for 1 year, compounded every year (in ₹).
- 12.Find the compound interest on ₹56700 at 10% per year for 2 years, compounded every year (in ₹).
- 13.A scooter is worth ₹53600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹2300 at 10% per year for 2 years (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
- 16.What amount will ₹45400 grow to in 1 year at 12% per year compound interest (in ₹)?
- 17.Find the compound interest on ₹7100 at 15% per year for 1 year, compounded every year (in ₹).
- 18.What amount will ₹47000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹54400 at 5% per year for 2 years (in ₹)?
- 20.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 21.What amount will ₹4800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 22.A scooter is worth ₹12500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹22400 at 5% per year for 2 years (in ₹)?
- 24.A town has 60000 people. The population grows by 4% every year. What will the population be after 2 years?
- 25.What amount will ₹2600 grow to in 1 year at 10% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹44000 at 20% per year for 1 year, compounded every year (in ₹).
- 27.A town has 32600 people. The population grows by 5% every year. What will the population be after 1 year?
- 28.What amount will ₹52500 grow to in 1 year at 20% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
- 30.A town has 11500 people. The population grows by 20% every year. What will the population be after 1 year?
- 31.What amount will ₹30400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 32.A town has 25000 people. The population grows by 20% every year. What will the population be after 3 years?
- 33.Find the compound interest on ₹30800 at 4% per year for 1 year, compounded every year (in ₹).
- 34.A town has 28200 people. The population grows by 20% every year. What will the population be after 1 year?
- 35.Find the compound interest on ₹32100 at 12% per year for 1 year, compounded every year (in ₹).
- 36.What is the difference between the compound interest and the simple interest on ₹4300 at 10% per year for 2 years (in ₹)?
- 37.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 38.A town has 55000 people. The population grows by 8% every year. What will the population be after 2 years?
- 39.What amount will ₹16200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 40.What amount will ₹54100 grow to in 2 years at 10% per year compound interest (in ₹)?
Answer key
- 7936
- 18375
- 209
- 22464
- 320
- 39900
- 4096
- 8112
- 17673
- 2704
- 2820
- 11907
- 48374
- 23
- 684
- 50848
- 1065
- 62557
- 136
- 34992
- 9375
- 10125
- 56
- 64896
- 2860
- 8800
- 34230
- 63000
- 4284
- 13800
- 33516
- 43200
- 1232
- 33840
- 3852
- 43
- 14580
- 64152
- 17010
- 65461
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