Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 940 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹57000 at 4% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
5. 5.A town has 7500 people. The population grows by 4% every year. What will the population be after 2 years?
6. 6.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹13200 at 5% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹59200 at 15% per year for 2 years (in ₹)?
9. 9.What amount will ₹5500 grow to in 3 years at 20% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹21100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
11. 11.A scooter is worth ₹54700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
12. 12.What amount will ₹58000 grow to in 1 year at 12% per year compound interest (in ₹)?
13. 13.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
14. 14.What amount will ₹37900 grow to in 1 year at 4% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹58000 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.A scooter is worth ₹55000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
17. 17.Find the compound interest on ₹53100 at 10% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹20600 at 8% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹26600 grow to in 2 years at 10% per year compound interest (in ₹)?
21. 21.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
23. 23.A scooter is worth ₹20000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
24. 24.Find the compound interest on ₹42300 at 4% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹59200 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹40700 at 25% per year for 1 year, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹41700 at 20% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹37200 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹2400 at 5% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
31. 31.A town has 28000 people. The population grows by 15% every year. What will the population be after 2 years?
32. 32.A town has 3000 people. The population grows by 10% every year. What will the population be after 3 years?
33. 33.Find the compound interest on ₹10800 at 5% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹41000 at 10% per year for 3 years, compounded every year (in ₹).
35. 35.What amount will ₹40000 grow to in 3 years at 10% per year compound interest (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹19200 at 10% per year for 2 years (in ₹)?
37. 37.A town has 16600 people. The population grows by 10% every year. What will the population be after 2 years?
38. 38.A scooter is worth ₹7500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
39. 39.Find the compound interest on ₹30000 at 5% per year for 2 years, compounded every year (in ₹).
40. 40.What amount will ₹15000 grow to in 1 year at 15% per year compound interest (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets