Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹44700 grow to in 2 years at 10% per year compound interest (in ₹)?
- 2.Find the compound interest on ₹60000 at 10% per year for 3 years, compounded every year (in ₹).
- 3.A scooter is worth ₹57600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 4.Find the compound interest on ₹46400 at 20% per year for 1 year, compounded every year (in ₹).
- 5.A scooter is worth ₹58400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 6.What amount will ₹28000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 7.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
- 8.What is the difference between the compound interest and the simple interest on ₹40600 at 20% per year for 2 years (in ₹)?
- 9.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 10.A scooter is worth ₹28000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 11.A town has 28000 people. The population grows by 20% every year. What will the population be after 3 years?
- 12.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 13.A scooter is worth ₹33500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 14.What amount will ₹25900 grow to in 2 years at 20% per year compound interest (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹23300 at 10% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
- 18.What amount will ₹2900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 19.A town has 14400 people. The population grows by 25% every year. What will the population be after 2 years?
- 20.A town has 5500 people. The population grows by 20% every year. What will the population be after 3 years?
- 21.A town has 32000 people. The population grows by 25% every year. What will the population be after 3 years?
- 22.What is the difference between the compound interest and the simple interest on ₹34400 at 15% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹56500 at 20% per year for 3 years, compounded every year (in ₹).
- 24.What amount will ₹10000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹5100 at 10% per year for 2 years (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 27.A town has 5200 people. The population grows by 25% every year. What will the population be after 2 years?
- 28.What amount will ₹3400 grow to in 2 years at 20% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹16000 at 20% per year for 2 years (in ₹)?
- 30.Find the compound interest on ₹29600 at 25% per year for 2 years, compounded every year (in ₹).
- 31.What is the difference between the compound interest and the simple interest on ₹37800 at 10% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
- 33.A town has 31600 people. The population grows by 20% every year. What will the population be after 2 years?
- 34.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 35.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 36.What is the difference between the compound interest and the simple interest on ₹23000 at 10% per year for 2 years (in ₹)?
- 37.A scooter is worth ₹49800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 38.Find the compound interest on ₹11500 at 8% per year for 1 year, compounded every year (in ₹).
- 39.What amount will ₹55700 grow to in 1 year at 8% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
Answer key
- 54087
- 19860
- 32400
- 9280
- 42194
- 37268
- 36501
- 1624
- 6305
- 15750
- 48384
- 40460
- 17152
- 37296
- 320
- 233
- 256
- 3625
- 22500
- 9504
- 62500
- 774
- 41132
- 13225
- 51
- 128
- 8125
- 4896
- 640
- 16650
- 378
- 3180
- 45504
- 24336
- 25002
- 230
- 47310
- 920
- 60156
- 16
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