Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹41200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 2.What amount will ₹26400 grow to in 1 year at 8% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
- 4.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹57700 at 5% per year for 1 year, compounded every year (in ₹).
- 7.What amount will ₹7700 grow to in 1 year at 20% per year compound interest (in ₹)?
- 8.What amount will ₹36200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹57200 at 15% per year for 2 years, compounded every year (in ₹).
- 10.Find the compound interest on ₹59000 at 5% per year for 1 year, compounded every year (in ₹).
- 11.A scooter is worth ₹31000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 12.A town has 17600 people. The population grows by 5% every year. What will the population be after 2 years?
- 13.Find the compound interest on ₹19100 at 25% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹4300 at 20% per year for 2 years, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹34000 at 10% per year for 2 years (in ₹)?
- 17.What amount will ₹48400 grow to in 1 year at 12% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
- 19.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 20.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 21.What amount will ₹41300 grow to in 1 year at 15% per year compound interest (in ₹)?
- 22.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 23.A town has 2400 people. The population grows by 5% every year. What will the population be after 2 years?
- 24.A town has 35000 people. The population grows by 4% every year. What will the population be after 2 years?
- 25.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 26.A town has 26400 people. The population grows by 25% every year. What will the population be after 2 years?
- 27.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹47000 at 4% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹53400 at 20% per year for 1 year, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹56000 at 5% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹58300 at 5% per year for 1 year, compounded every year (in ₹).
- 32.A scooter is worth ₹10400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 33.A town has 2800 people. The population grows by 5% every year. What will the population be after 2 years?
- 34.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 35.What amount will ₹37500 grow to in 1 year at 20% per year compound interest (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹53600 at 25% per year for 2 years (in ₹)?
- 37.What amount will ₹24800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹18800 at 5% per year for 2 years, compounded every year (in ₹).
- 39.Find the compound interest on ₹37000 at 10% per year for 3 years, compounded every year (in ₹).
- 40.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
Answer key
- 23175
- 28512
- 14895
- 19652
- 80
- 2885
- 9240
- 39820
- 18447
- 2950
- 22599
- 19404
- 4775
- 16
- 1892
- 340
- 54208
- 67
- 24565
- 46305
- 47495
- 37908
- 2646
- 37856
- 29478
- 41250
- 3180
- 1880
- 10680
- 140
- 2915
- 9568
- 3087
- 576
- 45000
- 3350
- 27342
- 1927
- 12247
- 48668
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