Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 955 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
2. 2.What amount will ₹32400 grow to in 1 year at 20% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹20500 at 20% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹3200 grow to in 1 year at 15% per year compound interest (in ₹)?
5. 5.What amount will ₹38000 grow to in 3 years at 10% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
7. 7.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
9. 9.A town has 18700 people. The population grows by 5% every year. What will the population be after 1 year?
10. 10.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
11. 11.Find the compound interest on ₹19100 at 5% per year for 1 year, compounded every year (in ₹).
12. 12.Find the compound interest on ₹2700 at 20% per year for 2 years, compounded every year (in ₹).
13. 13.A town has 18400 people. The population grows by 15% every year. What will the population be after 2 years?
14. 14.What amount will ₹56900 grow to in 1 year at 12% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹52800 at 5% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹15000 at 20% per year for 2 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹22000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
19. 19.A town has 48000 people. The population grows by 20% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹54700 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹17200 at 5% per year for 2 years (in ₹)?
25. 25.What amount will ₹55000 grow to in 2 years at 8% per year compound interest (in ₹)?
26. 26.What amount will ₹8400 grow to in 1 year at 25% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
28. 28.What amount will ₹46200 grow to in 1 year at 8% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹35900 at 10% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹6400 at 20% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹54800 grow to in 2 years at 25% per year compound interest (in ₹)?
32. 32.A town has 30000 people. The population grows by 4% every year. What will the population be after 2 years?
33. 33.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
34. 34.A scooter is worth ₹45000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
35. 35.A scooter is worth ₹7500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
36. 36.A town has 50000 people. The population grows by 12% every year. What will the population be after 2 years?
37. 37.What amount will ₹12900 grow to in 1 year at 25% per year compound interest (in ₹)?
38. 38.A town has 51000 people. The population grows by 5% every year. What will the population be after 1 year?
39. 39.What is the difference between the compound interest and the simple interest on ₹6800 at 15% per year for 2 years (in ₹)?
40. 40.What amount will ₹24000 grow to in 1 year at 25% per year compound interest (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets