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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 958 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹4700 grow to in 1 year at 8% per year compound interest (in ₹)?
  2. 2.A scooter is worth ₹55600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  3. 3.A scooter is worth ₹19800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  4. 4.A scooter is worth ₹35100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
  6. 6.A scooter is worth ₹18000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  7. 7.A scooter is worth ₹45000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  8. 8.Find the compound interest on ₹24100 at 4% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹31600 at 20% per year for 2 years (in ₹)?
  11. 11.A scooter is worth ₹33800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  12. 12.A town has 51600 people. The population grows by 25% every year. What will the population be after 2 years?
  13. 13.Find the compound interest on ₹55600 at 20% per year for 1 year, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹51100 at 12% per year for 1 year, compounded every year (in ₹).
  15. 15.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹22900 at 12% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹9000 at 10% per year for 3 years, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹13000 at 4% per year for 1 year, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹37600 at 15% per year for 2 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹52000 at 15% per year for 2 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹8900 at 20% per year for 2 years (in ₹)?
  24. 24.What amount will ₹42700 grow to in 2 years at 20% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹18000 at 25% per year for 2 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
  27. 27.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?
  28. 28.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹47600 at 5% per year for 2 years (in ₹)?
  30. 30.Find the compound interest on ₹18500 at 12% per year for 1 year, compounded every year (in ₹).
  31. 31.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
  32. 32.What amount will ₹34300 grow to in 2 years at 20% per year compound interest (in ₹)?
  33. 33.A town has 19200 people. The population grows by 25% every year. What will the population be after 3 years?
  34. 34.Find the compound interest on ₹55200 at 20% per year for 1 year, compounded every year (in ₹).
  35. 35.A scooter is worth ₹30000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  36. 36.Find the compound interest on ₹21600 at 25% per year for 2 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹43200 at 25% per year for 3 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
  40. 40.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?

Answer key

  1. 5076
  2. 31275
  3. 18810
  4. 33345
  5. 24
  6. 13005
  7. 41472
  8. 964
  9. 18928
  10. 1264
  11. 29744
  12. 80625
  13. 11120
  14. 6132
  15. 59584
  16. 2748
  17. 3310
  18. 2979
  19. 28
  20. 520
  21. 12126
  22. 16770
  23. 356
  24. 61488
  25. 10125
  26. 144
  27. 34496
  28. 55566
  29. 119
  30. 2220
  31. 414
  32. 49392
  33. 37500
  34. 11040
  35. 27075
  36. 12150
  37. 8334
  38. 41175
  39. 416
  40. 39930

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