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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 965 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹33600 at 15% per year for 2 years (in ₹)?
  2. 2.A scooter is worth ₹21600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  3. 3.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
  4. 4.What is the difference between the compound interest and the simple interest on ₹16700 at 10% per year for 2 years (in ₹)?
  5. 5.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹12900 at 20% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
  9. 9.What amount will ₹37000 grow to in 3 years at 10% per year compound interest (in ₹)?
  10. 10.What amount will ₹2000 grow to in 1 year at 5% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹17700 at 25% per year for 1 year, compounded every year (in ₹).
  14. 14.What amount will ₹6000 grow to in 2 years at 5% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹59500 at 15% per year for 1 year, compounded every year (in ₹).
  16. 16.A scooter is worth ₹54300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹34500 at 10% per year for 2 years (in ₹)?
  18. 18.A town has 30800 people. The population grows by 15% every year. What will the population be after 1 year?
  19. 19.A scooter is worth ₹8500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  20. 20.What amount will ₹37500 grow to in 2 years at 4% per year compound interest (in ₹)?
  21. 21.A town has 3200 people. The population grows by 5% every year. What will the population be after 2 years?
  22. 22.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  23. 23.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹46900 at 12% per year for 1 year, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹11300 at 10% per year for 2 years, compounded every year (in ₹).
  27. 27.What amount will ₹35600 grow to in 2 years at 15% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
  29. 29.What amount will ₹45000 grow to in 2 years at 12% per year compound interest (in ₹)?
  30. 30.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
  31. 31.What amount will ₹24000 grow to in 2 years at 15% per year compound interest (in ₹)?
  32. 32.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
  33. 33.What amount will ₹41900 grow to in 2 years at 10% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹4900 at 12% per year for 1 year, compounded every year (in ₹).
  35. 35.A town has 25000 people. The population grows by 12% every year. What will the population be after 2 years?
  36. 36.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹10600 at 10% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹28400 at 25% per year for 2 years, compounded every year (in ₹).
  40. 40.What amount will ₹24000 grow to in 3 years at 20% per year compound interest (in ₹)?

Answer key

  1. 756
  2. 17280
  3. 64827
  4. 167
  5. 24334
  6. 516
  7. 396
  8. 10812
  9. 49247
  10. 2100
  11. 180
  12. 5044
  13. 4425
  14. 6615
  15. 8925
  16. 43983
  17. 345
  18. 35420
  19. 6800
  20. 40560
  21. 3528
  22. 40656
  23. 1632
  24. 828
  25. 5628
  26. 2373
  27. 47081
  28. 137
  29. 56448
  30. 28224
  31. 31740
  32. 35152
  33. 50699
  34. 588
  35. 31360
  36. 54080
  37. 106
  38. 2522
  39. 15975
  40. 41472

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