Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹37200 at 20% per year for 2 years (in ₹)?
- 2.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹43300 at 20% per year for 1 year, compounded every year (in ₹).
- 4.A scooter is worth ₹35000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 5.A scooter is worth ₹3000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 6.What amount will ₹4000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 7.Find the compound interest on ₹40000 at 25% per year for 3 years, compounded every year (in ₹).
- 8.Find the compound interest on ₹10400 at 5% per year for 2 years, compounded every year (in ₹).
- 9.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 10.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹19600 at 15% per year for 2 years (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹7600 at 10% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹21000 at 10% per year for 2 years (in ₹)?
- 14.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹19200 at 25% per year for 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹22400 at 10% per year for 1 year, compounded every year (in ₹).
- 18.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹56000 at 15% per year for 2 years (in ₹)?
- 20.A town has 31000 people. The population grows by 10% every year. What will the population be after 3 years?
- 21.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 22.A town has 13200 people. The population grows by 20% every year. What will the population be after 1 year?
- 23.What is the difference between the compound interest and the simple interest on ₹19700 at 20% per year for 2 years (in ₹)?
- 24.A town has 8500 people. The population grows by 20% every year. What will the population be after 3 years?
- 25.Find the compound interest on ₹18500 at 25% per year for 1 year, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
- 27.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
- 28.What is the difference between the compound interest and the simple interest on ₹7000 at 10% per year for 2 years (in ₹)?
- 29.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
- 30.A scooter is worth ₹14400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 31.What amount will ₹36800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
- 33.A town has 49600 people. The population grows by 25% every year. What will the population be after 3 years?
- 34.A town has 4800 people. The population grows by 10% every year. What will the population be after 2 years?
- 35.What amount will ₹41300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 36.What amount will ₹26800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 37.A town has 35600 people. The population grows by 5% every year. What will the population be after 2 years?
- 38.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
Answer key
- 1488
- 12167
- 8660
- 32256
- 2430
- 6250
- 38125
- 1066
- 27436
- 48668
- 441
- 76
- 210
- 25002
- 1200
- 648
- 2240
- 61236
- 1260
- 41261
- 24336
- 15840
- 788
- 14688
- 4625
- 256
- 10816
- 70
- 2448
- 6075
- 40572
- 864
- 96875
- 5808
- 45430
- 29547
- 39249
- 7986
- 9152
- 1206
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