Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹58300 grow to in 1 year at 4% per year compound interest (in ₹)?
- 2.A scooter is worth ₹10100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 3.Find the compound interest on ₹48000 at 25% per year for 2 years, compounded every year (in ₹).
- 4.Find the compound interest on ₹10000 at 20% per year for 3 years, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹2800 at 15% per year for 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹35200 at 20% per year for 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹31200 at 20% per year for 2 years (in ₹)?
- 8.A scooter is worth ₹23000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 9.A town has 54900 people. The population grows by 4% every year. What will the population be after 1 year?
- 10.A town has 20900 people. The population grows by 12% every year. What will the population be after 1 year?
- 11.Find the compound interest on ₹40000 at 20% per year for 1 year, compounded every year (in ₹).
- 12.A scooter is worth ₹55900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 13.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹31700 at 25% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
- 16.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
- 17.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹14400 at 20% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹59500 at 10% per year for 2 years (in ₹)?
- 20.A town has 24500 people. The population grows by 8% every year. What will the population be after 1 year?
- 21.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹50800 at 5% per year for 2 years (in ₹)?
- 23.What amount will ₹8300 grow to in 1 year at 4% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹28000 at 5% per year for 2 years (in ₹)?
- 25.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
- 28.A town has 44000 people. The population grows by 20% every year. What will the population be after 3 years?
- 29.What is the difference between the compound interest and the simple interest on ₹59900 at 10% per year for 2 years (in ₹)?
- 30.What amount will ₹54000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 31.Find the compound interest on ₹47800 at 5% per year for 1 year, compounded every year (in ₹).
- 32.Find the compound interest on ₹31500 at 20% per year for 3 years, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹14800 at 15% per year for 2 years (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹43800 at 10% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹42200 at 5% per year for 1 year, compounded every year (in ₹).
- 36.A scooter is worth ₹16600. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 37.A town has 58400 people. The population grows by 20% every year. What will the population be after 2 years?
- 38.What is the difference between the compound interest and the simple interest on ₹51500 at 20% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹4000 at 5% per year for 2 years (in ₹)?
Answer key
- 60632
- 8181
- 27000
- 7280
- 63
- 1408
- 1248
- 11776
- 57096
- 23408
- 8000
- 44720
- 58320
- 7925
- 108
- 14580
- 32448
- 576
- 595
- 26460
- 8736
- 127
- 8632
- 70
- 9261
- 130
- 20835
- 76032
- 599
- 59535
- 2390
- 22932
- 333
- 438
- 2110
- 14608
- 84096
- 2060
- 1261
- 10
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