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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 974 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹57100 grow to in 1 year at 15% per year compound interest (in ₹)?
  2. 2.A scooter is worth ₹17600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  3. 3.Find the compound interest on ₹7600 at 5% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹40800 at 20% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹59300 at 20% per year for 1 year, compounded every year (in ₹).
  6. 6.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  7. 7.What amount will ₹27800 grow to in 1 year at 20% per year compound interest (in ₹)?
  8. 8.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹47200 at 15% per year for 2 years, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹52000 at 15% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
  12. 12.What amount will ₹10300 grow to in 1 year at 4% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹2200 at 20% per year for 1 year, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹18000 at 25% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹38900 at 8% per year for 1 year, compounded every year (in ₹).
  16. 16.A town has 35600 people. The population grows by 25% every year. What will the population be after 2 years?
  17. 17.Find the compound interest on ₹44900 at 25% per year for 1 year, compounded every year (in ₹).
  18. 18.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  19. 19.What amount will ₹56500 grow to in 2 years at 20% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹37500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  21. 21.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹14800 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹7700 grow to in 2 years at 10% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹22000 at 25% per year for 2 years (in ₹)?
  25. 25.A scooter is worth ₹45000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  26. 26.Find the compound interest on ₹47600 at 5% per year for 2 years, compounded every year (in ₹).
  27. 27.A town has 54400 people. The population grows by 15% every year. What will the population be after 2 years?
  28. 28.A scooter is worth ₹29600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  29. 29.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  30. 30.A town has 14000 people. The population grows by 5% every year. What will the population be after 2 years?
  31. 31.What is the difference between the compound interest and the simple interest on ₹16400 at 5% per year for 2 years (in ₹)?
  32. 32.A town has 14300 people. The population grows by 12% every year. What will the population be after 1 year?
  33. 33.Find the compound interest on ₹4300 at 20% per year for 2 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹55000 at 20% per year for 3 years, compounded every year (in ₹).
  35. 35.What amount will ₹27500 grow to in 2 years at 10% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹10000 at 15% per year for 2 years (in ₹)?
  37. 37.What amount will ₹20200 grow to in 2 years at 10% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  39. 39.A town has 7300 people. The population grows by 10% every year. What will the population be after 2 years?
  40. 40.What is the difference between the compound interest and the simple interest on ₹55900 at 10% per year for 2 years (in ₹)?

Answer key

  1. 65665
  2. 7425
  3. 779
  4. 1632
  5. 11860
  6. 55566
  7. 33360
  8. 100000
  9. 15222
  10. 1170
  11. 16668
  12. 10712
  13. 440
  14. 4500
  15. 3112
  16. 55625
  17. 11225
  18. 27783
  19. 81360
  20. 29040
  21. 6305
  22. 1480
  23. 9317
  24. 1375
  25. 34848
  26. 4879
  27. 71944
  28. 26714
  29. 12167
  30. 15435
  31. 41
  32. 16016
  33. 1892
  34. 40040
  35. 33275
  36. 225
  37. 24442
  38. 29169
  39. 8833
  40. 559

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