Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 979 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
2. 2.A town has 26100 people. The population grows by 20% every year. What will the population be after 1 year?
3. 3.What amount will ₹48000 grow to in 3 years at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹39300 at 15% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹41200 at 12% per year for 1 year, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹46800 at 20% per year for 2 years (in ₹)?
8. 8.A town has 47500 people. The population grows by 4% every year. What will the population be after 2 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹3700 at 10% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹50500 at 10% per year for 2 years, compounded every year (in ₹).
11. 11.What amount will ₹57000 grow to in 2 years at 20% per year compound interest (in ₹)?
12. 12.A town has 44800 people. The population grows by 25% every year. What will the population be after 3 years?
13. 13.What is the difference between the compound interest and the simple interest on ₹17200 at 5% per year for 2 years (in ₹)?
14. 14.What amount will ₹4800 grow to in 2 years at 5% per year compound interest (in ₹)?
15. 15.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
16. 16.A town has 36800 people. The population grows by 15% every year. What will the population be after 2 years?
17. 17.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
18. 18.A scooter is worth ₹9000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
19. 19.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹9000 at 20% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹58400 at 25% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹9300 at 25% per year for 1 year, compounded every year (in ₹).
23. 23.What amount will ₹3000 grow to in 3 years at 10% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹49600 at 15% per year for 2 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹24400 at 15% per year for 1 year, compounded every year (in ₹).
26. 26.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
27. 27.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
28. 28.What amount will ₹32900 grow to in 1 year at 15% per year compound interest (in ₹)?
29. 29.What amount will ₹29300 grow to in 1 year at 12% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹14300 at 8% per year for 1 year, compounded every year (in ₹).
31. 31.A scooter is worth ₹41600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
32. 32.A town has 38400 people. The population grows by 5% every year. What will the population be after 2 years?
33. 33.What is the difference between the compound interest and the simple interest on ₹53500 at 20% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹32500 at 8% per year for 1 year, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹46000 at 10% per year for 2 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
37. 37.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
38. 38.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
39. 39.Find the compound interest on ₹45600 at 4% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets