Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 982 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹39100 grow to in 1 year at 10% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹27200 at 15% per year for 2 years (in ₹)?
3. 3.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
4. 4.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).
5. 5.A town has 53500 people. The population grows by 20% every year. What will the population be after 3 years?
6. 6.A scooter is worth ₹20300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
7. 7.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹47500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
9. 9.What amount will ₹41700 grow to in 1 year at 5% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹54700 at 8% per year for 1 year, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹59200 at 5% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹20800 at 15% per year for 2 years (in ₹)?
14. 14.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹13300 at 5% per year for 1 year, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹21400 at 10% per year for 2 years (in ₹)?
20. 20.A town has 39800 people. The population grows by 10% every year. What will the population be after 2 years?
21. 21.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
22. 22.A scooter is worth ₹17500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
23. 23.Find the compound interest on ₹32800 at 12% per year for 1 year, compounded every year (in ₹).
24. 24.What amount will ₹37000 grow to in 2 years at 10% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹18000 at 15% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹49700 at 8% per year for 1 year, compounded every year (in ₹).
28. 28.A town has 35000 people. The population grows by 10% every year. What will the population be after 3 years?
29. 29.A scooter is worth ₹37500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
30. 30.A scooter is worth ₹57500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
31. 31.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
32. 32.What is the difference between the compound interest and the simple interest on ₹14000 at 25% per year for 2 years (in ₹)?
33. 33.A town has 10800 people. The population grows by 25% every year. What will the population be after 2 years?
34. 34.What amount will ₹41000 grow to in 1 year at 15% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹17000 grow to in 3 years at 10% per year compound interest (in ₹)?
38. 38.A town has 60000 people. The population grows by 20% every year. What will the population be after 3 years?
39. 39.A town has 16400 people. The population grows by 25% every year. What will the population be after 2 years?
40. 40.What is the difference between the compound interest and the simple interest on ₹12400 at 25% per year for 2 years (in ₹)?

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